java - 如何将捕获的图像路径从imageview保存到mysql数据库

Question

我想知道是否有人可以帮助我，我正在 Android 上创建表单，并且用户必须插入图像。应用程序打开相机，用户可以拍照并将该图像设置为 ImageView 。我的问题是如何获取 imageview 的图像路径以使用 php 将其保存到 mysql 数据库。

private void captureImage() {
        Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);


        fileUri = getOutputMediaFileUri(MEDIA_TYPE_IMAGE);

        intent.putExtra(MediaStore.EXTRA_OUTPUT, fileUri);

        // start the image capture Intent
        startActivityForResult(intent, CAMERA_CAPTURE_IMAGE_REQUEST_CODE);
    }



    @Override
    protected void onSaveInstanceState(Bundle outState) {
        super.onSaveInstanceState(outState);

        // save file url in bundle as it will be null on screen orientation
        // changes
        outState.putParcelable("file_uri", fileUri);
    }

    @Override
    protected void onRestoreInstanceState(Bundle savedInstanceState) {
        super.onRestoreInstanceState(savedInstanceState);

        // get the file url
        fileUri = savedInstanceState.getParcelable("file_uri");
    }




    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        // if the result is capturing Image
        if (requestCode == CAMERA_CAPTURE_IMAGE_REQUEST_CODE) {
            if (resultCode == RESULT_OK) {


                filePath = getPath(fileUri);

                final Bitmap image = BitmapFactory.decodeFile(filePath);

                image1.setImageBitmap(image);

            } else if (resultCode == RESULT_CANCELED) {

                // user cancelled Image capture
                Toast.makeText(getApplicationContext(),
                        "No picture for your Schedule", Toast.LENGTH_SHORT)
                        .show();

            } else {
                // failed to capture image
                Toast.makeText(getApplicationContext(),
                        "Sorry! Failed to capture image", Toast.LENGTH_SHORT)
                        .show();
            }

        }
        }

Answer 1

嗯，我想你已经拥有了你需要的东西。当您使用时:

filePath = getPath(fileUri);

这里有 Uri 和路径。现在有了这些信息，您应该在服务器中的 savePath.php 文件中创建一个 HttpPost。您必须在 AsyncTask 内发出请求。

http://www.androidsnippets.com/executing-a-http-post-request-with-httpclient