gpt4 book ai didi

php - android中发送json对象数据到远程mysql数据库

转载 作者:行者123 更新时间:2023-11-29 22:31:17 25 4
gpt4 key购买 nike

我已使用互联网上发布的方法成功从远程数据库获取数据。但我无法将数据推送(插入)到同一个表中。我添加了一个静态计数器只是为了检查代码是否到达给定的 url,但正如预期的那样,它失败了。下面是我在远程服务器文件管理器中保存的 php 文件。

<?php 
$json=$_GET [ 'json']; $json=f ile_get_contents( 'php://input');
$obj=json_decode($json);
$conn=mysql_connect( "mydatabasename", "myusername", "mypassword") or die( "error connecting");
mysql_select_db( "mydatabasename",$conn)or die("database couldnot connect");
error_reporting(E_ALL);
$tid=$_POST[ 'tid'];
$name=$_POST[ 'name'];
mysql_query( "insert into mytablename(tid,name) values($tid,$name)");
?>

我在 android 布局、tid、名称中获取了两个输入,并尝试发送到远程数据库。注意:出于安全目的,数据库名称和其他详细信息已被隐藏。

最佳答案

如果您正在寻找一种干净的方式..我建议您这样做:注册.php

  <?php
include('connect.php');
$response = array();
if (isset($_POST['Nom']) && isset($_POST['Prenom']) && isset($_POST['Email'])&& isset($_POST['Mdp'])) { //checking if the required fields are set

$Nom = $_POST['Nom'];//the family name
$Prenom = $_POST['Prenom']; //last name
$Email = $db->real_escape_string($_POST['Email']);
$Mdp = $db->real_escape_string($_POST['Mdp']); //the password

if ($res = $db->query("SELECT * FROM `patient` WHERE `Email_p`='$Email' ")) {
$row_cnt = $res->num_rows; }
if($row_cnt>0) {
$response["success"] = 0;
$response["message"] = "Email exists"; }
if ($row_cnt <1){
$result = mysqli_query($db,"INSERT INTO `patient`(`Id_p`, `Nom`, `Prenom`, `Email_p`, `Mdp`) VALUES ('','$Nom','$Prenom','$Email','$Mdp')");

if ($result ) {
$response["success"] = 1; // if account created we set success value to 1
$response["message"] = "account created";
} else {
$response["success"] = 0;
$response["message"] = "Oops Error";
}}
}else {
$response["success"] = 0;
$response["message"] = "Fields messing";


}
echo json_encode($response);
?>

在 android ... yourActivity.java

  class CreerNouveauCompte extends AsyncTask<String, String, String> {

@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(inscription.this);
pDialog.setMessage(getString(R.string.inscriEnCours));
pDialog.setIndeterminate(false);
pDialog.setCancelable(true);
pDialog.show();
}

protected String doInBackground(String... args) {
String nom = edtNom.getText().toString();
String prenom = edtPrenom.getText().toString();
String email = edtEmail.getText().toString();
String mdp = edtMdp.getText().toString();
JSONObject json;
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("Nom", nom));
params.add(new BasicNameValuePair("Prenom", prenom));
params.add(new BasicNameValuePair("Email", email));
params.add(new BasicNameValuePair("Mdp", mdp));

json= jsonParser.makeHttpRequest(url_register (your url),
"POST", params);
}
try {if(json != null && !json.isNull("success")){
int success = json.getInt("success");
s2=json.getString("message");
if (success == 1) { //the acount created
Intent intent;
SharedPreferences settings = getSharedPreferences("compte", 0);
SharedPreferences.Editor editor = settings.edit();
editor.putString("nom",edtNom.getText().toString() );
editor.putString("prenom",edtPrenom.getText().toString() );
editor.putString("email",edtEmail.getText().toString());
editor.putString("mdp",edtMdp.getText().toString());

editor.apply();
intent = new Intent(inscription.this,MainActivity.class);

}
startActivity(intent);
finish();
} else {
}}
} catch (JSONException e) {
e.printStackTrace();
}

return null;
}

protected void onPostExecute(String file_url) {
pDialog.dismiss();
}

}

call it like this
new CreerNouveauCompte().execute();

connect.php

 <?php  
$db = new mysqli('localhost', 'root', '', 'rechmed');
mysqli_set_charset($db,'utf8');
?>
//note i use mysqli ..in your case use mysql

关于php - android中发送json对象数据到远程mysql数据库,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29757910/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com