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php - Zend_Db_Table_Row 类的对象无法转换为字符串

转载 作者:行者123 更新时间:2023-11-29 22:27:30 25 4
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当我运行以下命令时,我在标题中收到错误消息:

$year = date('Y');
$month = date('n');
$day = date('j') - 3;
$week = date('W') - 1;

$select = "SELECT IF( station_name = '', 'Unknown', station_name ) station_name, station_name as db_name, sum(case when year(print_date) = $year then print_pages end) as yearpages, sum(case when (month(print_date) = $month and year(print_date) = $year) then print_pages end) as monthpages, sum(case when (day(print_date) = $day and year(print_date) = $year and month(print_date) = $month) then print_pages end) as daypages, sum(case when (week(print_date) = $week AND year(print_date) = $year AND month(print_date) = $month) then print_pages end) as weekpages
FROM `file_prints`
GROUP BY station_name;";

$rows = $_userTable->getAdapter()->fetchAll($select);
foreach($rows as $key => $row)
{
$oModelStation = new Application_Model_PrintStation();
$fPrintsModel = new Application_Model_FilePrints();
$station = $oModelStation->fetchRow($oModelStation->select()->where('name = ?', $row['station_name']));
$row['weekpages'] = $fPrintsModel->fetchRow($fPrintsModel
->select(array('sum(print_pages) as weekpages'))
->where('station_name = ?', $row['station_name']));
->where('year(print_date) = ?', $year)
->where('week(print_date) = ?', $week));

echo $row['weekpages'];

错误可以追溯到最后一行,即此示例代码(echo $row['weekpages'])。我已经通过初始 $select SQL 查询的回显测试了结果,它似乎令人满意,并且我尝试删除 fetchRow 执行中的各种 where 条件,以查看是否有一个条件是罪魁祸首,但我不断收到相同的错误消息。

此外,当我使用此代码执行 var_dump($row) 时,我看到 weekpages 的键指向 Zend 对象,而日页、月页和年页的所有其他键都指向包含数值的字符串。

最佳答案

错误消息告诉您问题是什么。 fetchRow() 返回一个 Zend_Db_Table_Row 对象,然后将其存储在索引“weekpages”的数组中。我不确定您打算如何处理检索到的行中的数据,但您可以尝试使用 ->toArray() 将行对象转换为数组或访问行对象的各个字段,如下所示:

echo $row['weekpages']->weekpages;

假设您打算让 $row['weekpages'] 保存行对象,尽管您选择的索引字符串让我认为情况可能并非如此。

为了额外说明,$row['weekpages'] 的值是行对象,并且您在查询中使用别名的列也称为“weekpages”。

关于php - Zend_Db_Table_Row 类的对象无法转换为字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30145140/

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