javascript - 如何显示来自 JsonRestStore 的数据

Question

以下是我编写的代码示例。我想从 REST 服务获取数据并将其打印在屏幕上。我可以从 REST 获得 JSON 格式的响应。但是，我找不到将它存储在 JSONStore 中并使用它的方法。请帮我解决这个问题。

dojo.provide("index.IndexService");
dojo.require("dojo.parser"); 
dojo.require("dijit.Editor"); 
dojo.require("dijit.form.Button");
dojo.require("dijit.layout.BorderContainer"); 
dojo.require("dijit.layout.TabContainer");
dojo.require("dijit.layout.ContentPane");
dojo.require("dojox.data.JsonRestStore");
var xhrArgs = {
        url: "http://localhost:8080/RestApp/service/customers",
        handleAs: "json",
        contentType : "application/json",
        load: function(data){
          alert(data);
        },
        error: function(error){
            alert(error);
        }
      }

dojo.ready(function(){
    // Create a button programmatically:
    var button = new dijit.form.Button({
        label: "View Transactions...",
        onClick: function(){
            // Do something:
            dojo.byId("result1").innerHTML += "Functionality yet to be implemented! ";
        }
    }, "progButtonNode");
    alert('hi');
    var store = new dojox.data.JsonRestStore({target: "http://localhost:8080/RestApp/service/customers"});

    alert(store);

    store.get(1).when(function(object){
        alert(object);
        // use the object with the identity of 3
      });



    //var deferred = dojo.xhrGet(xhrArgs);

    //compliantStore = new dojox.data.JsonRestStore({deferred});


    alert(deferred);
});

返回的JSON值为

{"employees":{"customers":[{"city":null,"accountNo":null,"name":"Name 1","id":1},{"city":null,"accountNo":null,"name":"Name 2","id":2}],"count":2}}

我将如何检索这些值？

Answer 1

JsonRestStore 项目实际上是简单的 JavaScript 对象，因此您始终可以直接从项目中读取属性。喜欢

var store = new dojox.data.JsonRestStore({target: "http://localhost:8080/RestApp/service/customers"});
myValue = recipeStore.getValue(item,"foo"); //stored in myValue
get = store.getValue;
set = store.setValue;
save = store.save;
// then fetch an item
var myGetValue = get(item,"foo");
var setMyValue = set(item,"foo","bar");

在同步模式下，通过直接访问从获取操作返回的请求对象的结果属性，可以在不提供回调的情况下获取:

var queryResults = store.fetch({query:"?tastes='good'"}).results;
var firstItem = queryResults[0];

你的意思是这样的..希望它有帮助