php - 从 while 循环获取单选按钮值

Question

如何从 while 循环中获取单选按钮的值？

这是我从数据库检索数据的代码:

<form action="verify.php" method="POST">
<?php
$con=mysqli_connect("localhost","root","","database");

// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

$sql = "SELECT * FROM question WHERE ID_Q LIKE 'A%'" ;
$result = mysqli_query($con,$sql);
$count=mysqli_num_rows($result);

$kira=1;
while($x = mysqli_fetch_array($result))
  {
  echo "<tr>";
  echo "<td>$kira.</td>";
  echo "<th>" . $x['Question']."</th>";
  echo "</tr>";
  echo "<tr>";
  echo "<td></td>";
  echo "<td>";
  $sql2 = "SELECT * FROM answer WHERE ID_question ='$x[ID_Q]'" ;
  $result2 = mysqli_query($con,$sql2);
  $count2=mysqli_num_rows($result2);
  while($y = mysqli_fetch_array($result2)){
      echo "<input type='radio' name=answer[".$x['ID_Q']."] value=val[".$y['weight_pre']."]>".$y['answer'];
     echo "<br>";
  }
  echo "</td>";
  //echo "<td>".$x['pic']."</td>";
  echo "</tr>";
  $kira++;
  }
?>
<button type="submit"> Kira </button>
</form>

这是我的“verify.php”

<?php
session_start();
$a=$_GET['name'];
$b=$_GET['value'];
$c=$_SESSION['ID_user'];

 if(!isset ($_SESSION['ID_user'])){
    echo "You have to log in to be able to view this page.";
    echo "<meta http-equiv='Refresh' content='1;index.php'>";
    die();
}
else {
    // Create connection
$con=mysqli_connect("localhost","root","","database");

// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }
$s=0;
while ($s<=20){
    $sql = "INSERT INTO answer_user(ID_user, ID_question, answer, 
weight) "."VALUES ('$c','$a','','$b')";
$result = mysqli_query($con,$sql);
$s++;
}

}
?>

那么，用户提交表单后如何获取单选按钮的值？谢谢。

Answer 1

您需要使用这个:

$_POST['radio'];

将“radio”替换为您的 radio 输入名称。