android - 单击按钮时如何从 ListView 中获取所选项目

Question

我有一个自定义 ListView ，我正在选择列表中的多个项目，现在我需要在单击按钮时获取这些项目名称，该按钮将调用 listfunction() 方法，您可以在下面的代码中看到这一点。

public class Places extends Activity {

    private ListView listView;

    private static int selectedListItem = -1;
    private Handler mHandler = new Handler();
    private static Vector<String> data; 

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.places_custom_list_view);
        data = new Vector<String>();

        // Add data as per your requirement   
        data.add("one");
        data.add("two");
        data.add("three");
        data.add("four");
        data.add("five");
        data.add("six");

        listView = (ListView)findViewById(R.id.ListView01);
        listView.setDivider(null);

        listView.setOnItemClickListener(new OnItemClickListener() {
            public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
                //System.out.println(EfficientAdapter.saveState.get(position));
                selectedListItem = position;
                ((EfficientAdapter)listView.getAdapter()).notifyDataSetChanged();
                if(EfficientAdapter.saveState.get(position)=="selected"){
                    EfficientAdapter.saveState.put(position,"unselected");
                }else
                EfficientAdapter.saveState.put(position,"selected");  
                mHandler.postDelayed(new Runnable() {

                    @Override
                    public void run() {
                        // call any new activity here or do any thing you want here         

                    }
               }, 200L);
            }
        });

        listView.setAdapter(new EfficientAdapter(getApplicationContext()));   
    }

    private static class EfficientAdapter extends BaseAdapter {
        private LayoutInflater mInflater;
        static HashMap<Integer,String> saveState=new HashMap<Integer,String>();

        public EfficientAdapter(Context context) {
            mInflater = LayoutInflater.from(context);
            for(int i=0;i<data.size();i++)
            {
               saveState.put(i,"unselected");
            }

        }

        public int getCount() {
            return data.size();
        }

        public Object getItem(int position) {
            return position;
        }

        public long getItemId(int position) {
            return position;
        }

        public View getView(int position, View convertView, ViewGroup parent) {

            ViewHolder holder;

            if (convertView == null || convertView.getTag() == null) {
                convertView = mInflater.inflate(R.layout.places_custom_row_view, null);
                holder = new ViewHolder();

                holder.txtName = (TextView) convertView
                    .findViewById(R.id.name);

                convertView.setTag(holder);
            } else {
                 holder = (ViewHolder) convertView.getTag();
            }


            if(saveState.get(position).equals("selected"))
                holder.txtName.setBackgroundResource(R.drawable.cellbghover);  

             else
                holder.txtName.setBackgroundResource(R.drawable.cellbgnew);

            holder.txtName.setText(data.get(position)); 

            return convertView;
        }
    }

    static class ViewHolder {
        TextView txtName;
    }

    public void listfunction(View button) {
        System.out.println("listfunction items are::::"+selectedListItem);

    }
    }

Answer 1

自定义 ListView 应该有自定义适配器。在自定义适配器中，您可以找到名为 getView() 的方法以及 View 、位置和父组。当您尝试点击事件时，位置将代表当前所选项目的索引。

public class MyArrayAdapter extends ArrayAdapter<String> {
    @Override
    public View getView(final int position, View convertView,ViewGroup parent) {
            }
}