php - preg_replace 特殊字符上的错误

Question

我想更改以下内容:
% =>\%
_ =>\_
\  =>\\

例如:

1. ali% sdn bhd -> ali\% sdn bhd
2. ali_ sdn bhd -> ali\_ sdn bhd
3. ali\ sdn bhd -> ali\\ sdn bhd

这是编写的代码:

<?php
$special_characters = array("%","_","\\");
$replace_special_characters = array("\\%","\\_","\\\\\\\\");

foreach($special_characters as $value)
{   
        if(strpos($companyname, $value) !== FALSE)
        {
            $companyname = preg_replace('/'.$value.'/', $replace_special_characters, $companyname);   //ERROR HERE
        }   
}
?>

但是，从上面的输出中，我收到此错误:

Warning: preg_replace(): Parameter mismatch, pattern is a string while replacement is an array ...

我哪部分写错了？我该如何修改？

Answer 1

问题是您无法使用 preg_replace 将字符串替换为数组。

您必须获取元素在数组中的位置，然后使用此位置进行替换:

<?php
$special_characters = array("%","_","\\");
$replace_special_characters = array("\\%","\\_","\\\\\\\\");

$i = 0; //set the original position
foreach($special_characters as $value)
{   
        if(strpos($companyname, $value) !== FALSE)
        {
            echo '/'.$value.'/';
            $companyname = preg_replace('/'.$value.'/', $replace_special_characters[$i], $companyname);   //Here you get replacement using the current position, so a string is set as replacement, not an array
        }   
        $i++;//after each value, you increment the position
}
?>

我不确定这段代码是否有效，但它向您展示了需要实现的逻辑。