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MYSQL 联合组依据

转载 作者:行者123 更新时间:2023-11-29 22:01:27 25 4
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我正在执行此选择语句:

SELECT * FROM (
SELECT COUNT(t.text) as count, COUNT(DISTINCT(t.from_user_id)) as usercount, DATE_FORMAT(t.created_at,'%Y-%m-%d %H:00') datepart
FROM TABLE1 t WHERE t.created_at >= '2015-08-12 00:00:00' AND t.created_at <= '2015-08-13 18:30:00' AND t.eliminar IS NULL
GROUP BY datepart) as t
UNION ALL
SELECT * FROM (
SELECT COUNT(b.id) as count, COUNT(DISTINCT(b.from_user_id)) as usercount, DATE_FORMAT(b.created_at,'%Y-%m-%d %H:00') datepart
FROM TABLE2 b WHERE b.created_at >= '2015-08-12 00:00:00' AND b.created_at <= '2015-08-13 18:30:00' AND b.eliminar IS NULL
GROUP BY datepart) as x GROUP BY datepart

这个选择得到这个:

enter image description here

我正在尝试使用 datepart 分组进行查看,但我不能,知道我做错了什么吗?

TABLE2 只有 (id,from_user_id,eliminar) 并且除了 created_at 之外都是 NULL,在这一行中我有整个 2015 年的逐日和小时,格式与 TABLE1 相同

最佳答案

已解决:

SELECT DISTINCT * FROM (
SELECT COUNT(t.text) as count, COUNT(DISTINCT(t.from_user_id)) as usercount, DATE_FORMAT(t.created_at,'%Y-%m-%d %H:00') datepart
FROM TABLE1 t WHERE t.created_at >= '2015-08-12 00:00:00' AND t.created_at <= '2015-08-13 18:30:00' AND t.eliminar IS NULL
GROUP BY datepart
UNION ALL
SELECT COUNT(t.id) as count, COUNT(DISTINCT(t.from_user_id)) as usercount, DATE_FORMAT(t.created_at,'%Y-%m-%d %H:00') datepart
FROM TABLE2 t WHERE t.created_at >= '2015-08-12 00:00:00' AND t.created_at <= '2015-08-13 18:30:00' AND t.eliminar IS NULL
GROUP BY datepart) as x GROUP BY datepart ORDER BY datepart

关于MYSQL 联合组依据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32613907/

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