android - 如何在 Post 方法上获取内容

Question

我已经为 HttpPost 使用了下面的代码，它执行成功了。但无法看到响应。我得到了 InputStream。我想知道里面的内容是什么。

我想显示为字符串格式。如何做到这一点。

        HttpPost httppost = new HttpPost(requestURL);
        ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(params.length);

        for (int postValueCount = 0; postValueCount < params.length; postValueCount++)
            nameValuePairs.add(new BasicNameValuePair(params[postValueCount][0],params[postValueCount][1]));

        try {
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
            Log.d("HttpPostRequest","URL : " + httppost.getRequestLine().getUri());
            Log.d("HttpPostRequest","Method : " + httppost.getRequestLine().getMethod());
            Log.d("HttpPostRequest","Parameters : " + nameValuePairs);
            response = httpclient.execute(httppost);
            status = response.getStatusLine();

            if (status.getReasonPhrase().equals("OK")) {
                httpEntity=response.getEntity();
                InputStream in = httpEntity.getContent();               
                return in;
            } else {
                Log.d("Http Status", status.getReasonPhrase());
            }

        }

Answer 1

使用这段代码:

HttpEntity entity = response.getEntity();
String response = EntityUtils.toString(entity);