mysql - 如何从mysql中的连接表中获取不相等的行？

Question

我有两个表如下

user_job_applied

company_viewed_user

我想将不在company_viewed_user表中的行作为user_job_applied表中的相关job_id。我为它编写了以下查询，但它没有被抓取

SELECT
    `user_job_applied`.user_id
FROM
    `user_job_applied`
LEFT JOIN 
    `company_viewed_user` 
ON 
    `company_viewed_user`.user_id ON `company_viewed_user`.user_id = `user_job_applied`.user_id                               
WHERE
    `company_viewed_user`.user_id IS NULL AND
    `company_viewed_user`.emp_id IN (SELECT user_id 
                                     FROM company_user 
                                     WHERE company_id='1') 
AND
    `user_job_applied`.job_id = '1'; 

输出应如下所示

Answer 1

想要将 emp_id 条件从 where 子句移至左连接语句

SELECT
`user_job_applied`.user_id
FROM
`user_job_applied`
LEFT JOIN `company_viewed_user` ON `company_viewed_user`.user_id = `user_job_applied`.user_id AND 
                                                                `company_viewed_user`.emp_id IN (SELECT user_id FROM company_user WHERE company_id='1')                             
WHERE
`company_viewed_user`.user_id IS NULL AND                        
`user_job_applied`.job_id = '1';