Android:显示另一个 Activity 的 Activity View

Question

嗨，我有两个 Activity ，第一个 Activity 有三个图标，一个是不可见的...当我点击第一个 Activity 时，它会使用 Intent 转到第二个 Activity ..我的第二个 Activity 是登录屏幕，当登录成功时我应该回到第一个 Activity 并在第一个 Activity 中显示一个图标..我怎样才能从第二个 Activity 返回到第一个 Activity 并使图标在第一个 Activity 中可见..下面是我的登录屏幕代码

public void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);

            setContentView(R.layout.fyelogin);                    
            etPassword = (EditText)findViewById(R.id.password);
            btnLogin = (Button)findViewById(R.id.login_button);
            btnCancel = (Button)findViewById(R.id.cancel_button);
            lblResult = (TextView)findViewById(R.id.result);

            final ImageView details = (ImageView)findViewById(R.id.red); 

            btnLogin.setOnClickListener(new OnClickListener() {
                public void onClick(View v) {

                    String password = etPassword.getText().toString();

                    if(password.equals("guest")){
                        lblResult.setText("password successful.");

              // details.setVisibility(View.VISIBLE);


                    } else {
                        lblResult.setText("password doesn't match.");

                    }                                      
                    finish();}});

感谢任何建议/帮助...

Answer 1

使用 startActivityforResult 打开登录 Activity ..然后在第一个 Activity 的 onActivityResult(int, int, Intent) 中显示图标..

例子:

public class MyActivity extends Activity {
 ...

 static final int PICK_CONTACT_REQUEST = 0;

 protected boolean onKeyDown(int keyCode, KeyEvent event) {
     if (keyCode == KeyEvent.KEYCODE_DPAD_CENTER) {
         // When the user center presses, let them pick a contact.
         startActivityForResult(
             new Intent(Intent.ACTION_PICK,
             new Uri("content://contacts")),
             PICK_CONTACT_REQUEST);
        return true;
     }
     return false;
 }

 protected void onActivityResult(int requestCode, int resultCode,
         Intent data) {
     if (requestCode == PICK_CONTACT_REQUEST) {
         if (resultCode == RESULT_OK) {
             // A contact was picked.  Here we will just display it
             // to the user.
             startActivity(new Intent(Intent.ACTION_VIEW, data));
         }
     }
 }
}

检查 http://developer.android.com/reference/android/app/Activity.html