javascript - Ajax jQuery 表单无法正常工作，导航到 PHP 文件

Question

我在使用 ajaxForm 插件时遇到问题。我希望它在不离开页面的情况下向用户显示结果消息。

问题是，当我提交表单时，它没有将警报添加到 .jumbotron.modded(这是表单的 div 容器)中，而是导航到 supportForm.php 并只显示回显的数字。

这有时效果很好，但大多数时候它只是导航到 supportForm.php 。我不明白为什么它并不总是具有相同的行为。

这是 HTML 表单:

        <form id="supportForm" action="supportForm.php" method="post" style="padding-top:10px">
            <div class="form-group">
                <input type="text" name="subject" id="subject" placeholder="Subject" class="form-control" required>
            </div>
            <div class="form-group">
                <textarea class="form-control" rows="4" name="comment" id="comment" placeholder="Write your message here" required></textarea>
            </div>
            <button type="submit" class="btn btn-upload" style="margin-top:20px;float:right;" value="">SEND<img src="img/plus.png" style="margin-bottom:5px;padding-left:5px;" /></button>
        </form>

这是 Javascript 代码:

    window.onload = function()
    {
        $('#supportForm').ajaxForm({
            success: function(res) {
                console.log(res);
                if(res=='1')
                {
                    $(".jumbotron.modded").prepend('<div class="alert alert-success alert-dismissible" role="alert">  <button type="button" class="close" data-dismiss="alert"><span aria-hidden="true">&times;</span><span class="sr-only">Close</span></button>Successfully sent. Thank you</div>');
                }else{
                    switch(res)
                    {
                        case '0':
                            $(".jumbotron.modded").prepend('<div class="alert alert-danger alert-dismissible" role="alert">  <button type="button" class="close" data-dismiss="alert"><span aria-hidden="true">&times;</span><span class="sr-only">Close</span></button>Error 1. Please contact mail@asd.com<</div>');
                        break;
                        case '-1':
                            $(".jumbotron.modded").prepend('<div class="alert alert-danger alert-dismissible" role="alert">  <button type="button" class="close" data-dismiss="alert"><span aria-hidden="true">&times;</span><span class="sr-only">Close</span></button>Error 2. Please contact mail@asd.com<</div>');
                        break;
                        case '-2':
                            $(".jumbotron.modded").prepend('<div class="alert alert-danger alert-dismissible" role="alert">  <button type="button" class="close" data-dismiss="alert"><span aria-hidden="true">&times;</span><span class="sr-only">Close</span></button>Error 3. Please contact mail@asd.com</div>');
                        break;
                        case '-3':
                            $(".jumbotron.modded").prepend('<div class="alert alert-danger alert-dismissible" role="alert">  <button type="button" class="close" data-dismiss="alert"><span aria-hidden="true">&times;</span><span class="sr-only">Close</span></button>Error 4. Please contact mail@asd.com<</div>');
                        break;
                    }
                }
            }
        });
    }

这是 PHP 代码:

if ($row = $db->query("SELECT user FROM tblusers WHERE userId='".$fromId."'")->fetch_array())
{
    $fromMail1 = $row['user'];
    if($row2 = $db->query("SELECT name,lastname,email FROM tblprofile WHERE userId='".$fromId."'")->fetch_array())
    {
        $fromMail2 = $row2['email'];
        $fromName = $row2['name']." ".$row2['lastname'];
        if ($db->query("INSERT INTO tblSupports (supportTitle,supportComment,userId) VALUES ('".$title."','".$comment."','".$fromId."')"))
        {
            if(sendEmail($fromMail1,$fromMail2,$fromName,$titleClean,$commentClean))
            {
                echo 1;
            }else{// (error 1)
                echo 0;
            }
        }else{//(error 2)
            echo -1;
        }
    }else{//(error 3)
        echo -2;
    }
}else{//(error 4)
    echo -3;
}

我该如何解决这个问题？非常感谢

Answer 1

试试这个

$('#supportForm').ajaxForm({
    /* bla-bla-bla*/

    return false;
    })

但是我真的不明白，你用这个插件是为了什么。无需任何插件即可轻松完成。

$('#submit').click(function(){
    $.ajax({
      method: "POST",
      url: "some.php",
      data: $('#supportForm').serialize(),
        success: function(data){
            alert(data)
        }
        error: function(error){
            alert(error);
        }
    });
    return false;
});

像这样。