android - listview android中的按钮位置

Question

我在 ListView 上有一个按钮，单击它会显示弹出窗口。我已经成功实现了。但问题是我想在点击的按钮位置显示弹出窗口。

View layout = inflater.inflate(R.layout.popup_layout,null);             
    pwindo = new PopupWindow(layout, 300, 250, true);
    pwindo.showAtLocation(layout, Gravity.NO_GRAVITY,  30, 40);
    pwindo.setOutsideTouchable(true);
    pwindo.setTouchable(true); 
    pwindo.setBackgroundDrawable(new BitmapDrawable());
    layout.setOnTouchListener(new OnTouchListener() {



            @Override
            public boolean onTouch(View v, MotionEvent event) {
                // TODO Auto-generated method stub
                pwindo.dismiss();
                return false;
            }
        });

按钮代码

 vi = inflater.inflate(R.layout.list_row, null);
vi.findViewById(R.id.statusImage).setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View arg0) {
            // TODO Auto-generated method stub
            showPopup();//to display popup thats given above
        }
    });

Answer 1

你需要设置buttons标签作为它的位置，onClick你需要获取它:

button.setTag(position);
button.setOnClickListener(new View.OnClickListener() { 
    public void onClick(View v) {
        int position = (Integer) v.getTag();
        // Do whatever you like with position
    }
});