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PHP MYSQL 多个 if 语句进行多个更新

转载 作者:行者123 更新时间:2023-11-29 21:39:17 26 4
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有人可以告诉我这些 IF 语句有什么问题吗?

if(isset($_POST['submit']))
{
$dropship = $unitid['id'];
$jumpship = $_POST['jumpship'];
$dsdest = $_POST['planet'];
$dslz = $_POST['landingzone'];
$dsmission = $_POST['mission'];
$ds1 = mysql_query("SELECT id, ds1 FROM gc3025_game_jumpships WHERE `id`='$jumpship'");
$ds2 = mysql_query("SELECT id, ds2 FROM gc3025_game_jumpships WHERE `id`='$jumpship'");
$ds3 = mysql_query("SELECT id, ds3 FROM gc3025_game_jumpships WHERE `id`='$jumpship'");

$dist_loc_get2 = mysql_query("SELECT * FROM gc3025_dist_game WHERE `planet`='$dsdest' AND `districtid`='$dslz'");
$distloc2 = mysql_fetch_assoc($dist_loc_get2);
$newdist = $distloc2['g_district'];
$ds_name_get = mysql_query("SELECT * FROM gc3025_game_dropships WHERE `id`='$dropship'");
$ds_name = mysql_fetch_assoc($ds_name_get);
$dsname = $ds_name['unit_name'];

$dest_name_get = mysql_query("SELECT gc3025_planets_game.Game, gc3025_planets_game.owners, gc3025_planets_game.g_planet, gc3025_planets_game.Planet_id, gc3025_planets_id.planet_name FROM gc3025_planets_id JOIN gc3025_planets_game ON gc3025_planets_id.id = gc3025_planets_game.Planet_id WHERE `g_planet`='$dsdest'");
$dest_name = mysql_fetch_assoc($dest_name_get);
$destname = $dest_name['planet_name'];

$dsdz_name_get = mysql_query("Select gc3025_dist_game.districtid, gc3025_dist_game.g_district, gc3025_dist_labels.id, gc3025_dist_labels.dist_name FROM gc3025_dist_game JOIN gc3025_dist_labels ON gc3025_dist_game.districtid = gc3025_dist_labels.id WHERE `g_district`='$newdist'");
$dsdz_name = mysql_fetch_assoc($dsdz_name_get);
$dsdzname = $dsdz_name['dist_name'];

$dsmission_name_get = mysql_query("SELECT * FROM gc3025_movement_dropdowns WHERE `id`='$dsmission'");
$dsmission_name = mysql_fetch_assoc($dsmission_name_get);
$dsmissionname = $dsmission_name['mission_type'];

if ($ds1 == 0){
mysql_query ("UPDATE `gc3025_game_jumpships` SET `ds1` = '$dsname', `ds1dest` = '$destname', `ds1dz` = '$dsdzname', `ds1mission` = '$dsmissionname' WHERE `id`='$jumpship'");
}
if ($ds1 == 1){
mysql_query ("UPDATE `gc3025_game_jumpships` SET `ds2` = '$dsname', `ds2dest` = '$destname', `ds2dz` = '$dsdzname', `ds2mission` = '$dsmissionname' WHERE `id`='$jumpship'");
}
if ($ds2 == 1){
mysql_query ("UPDATE `gc3025_game_jumpships` SET `ds3` = '$dsname', `ds3dest` = '$destname', `ds3dz` = '$dsdzname', `ds3mission` = '$dsmissionname' WHERE `id`='$jumpship'");
}
if ($ds3 == 1){
echo "This Jumpship is Full!";
}

echo "<p>$dsname Loaded on $jumpship going to $destname and to complete $dsmissionname In District $dsdzname!</p>";

希望这已经足够了。

基本上,该表适用于携带 3 艘运输船的跳跃船。我需要 if 语句基本上如果 ds1 中有一艘运输船,那么运输船将被输入到 ds2 列。如果 ds1 和 ds2 中有 dropship,那么它将更新 ds3 列。如果这三艘船中都有运输船,那么将发布“这艘运输船已满”的 echo 。

最佳答案

函数mysql_query返回resource ,并且必须使用mysql_fetch_assoc来提取数据。此外,查询中的数据应该是 properly escaped .

$ds_query = mysql_query(sprintf(
"SELECT ds1, ds2, ds3 FROM gc3025_game_jumpships WHERE `id`='%s'",
mysql_real_escape_string($jumpship)
));

$ds_result = mysql_fetch_assoc($ds_query);

if (!$ds_result['ds1'])
{
mysql_query(sprintf(
"UPDATE `gc3025_game_jumpships` " .
"SET `ds1` = '%s', `ds1dest` = '%s', `ds1dz` = '%s', `ds1mission` = '%s' " .
"WHERE `id`='%s'",
mysql_real_escape_string($dsname),
mysql_real_escape_string($destname),
mysql_real_escape_string($dsdzname),
mysql_real_escape_string($dsmissionname),
mysql_real_escape_string($jumpship)
));
}
elseif ($ds_result['ds1'])
{
// and so on
}
elseif ($ds_result['ds2'])
{
// and so on
}

关于PHP MYSQL 多个 if 语句进行多个更新,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34665897/

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