php - 如何将数据从 Javascript 传递到 PHP，反之亦然？

Question

这个问题已经有答案了:

How do I pass JavaScript variables to PHP? (16 个回答)

已关闭 3 年前。

如何通过 Javascript 脚本请求 PHP 页面并向其传递数据？那么我如何让 PHP 脚本将数据传递回 Javascript 脚本？

客户端.js:

data = {tohex: 4919, sum: [1, 3, 5]};
// how would this script pass data to server.php and access the response?

服务器.php:

$tohex = ... ; // How would this be set to data.tohex?
$sum = ...; // How would this be set to data.sum?
// How would this be sent to client.js?
array(base_convert($tohex, 16), array_sum($sum))

Answer 1

从 PHP 传递数据很容易，您可以用它生成 JavaScript。另一种方法有点困难 - 您必须通过 Javascript 请求调用 PHP 脚本。

示例(为简单起见，使用传统的事件注册模型):

<!-- headers etc. omitted -->
<script>
function callPHP(params) {
    var httpc = new XMLHttpRequest(); // simplified for clarity
    var url = "get_data.php";
    httpc.open("POST", url, true); // sending as POST

    httpc.onreadystatechange = function() { //Call a function when the state changes.
        if(httpc.readyState == 4 && httpc.status == 200) { // complete and no errors
            alert(httpc.responseText); // some processing here, or whatever you want to do with the response
        }
    };
    httpc.send(params);
}
</script>
<a href="#" onclick="callPHP('lorem=ipsum&foo=bar')">call PHP script</a>
<!-- rest of document omitted -->

无论 get_data.php 生成什么，都将出现在 httpc.responseText 中。错误处理、事件注册和跨浏览器 XMLHttpRequest 兼容性留给读者作为简单的练习;)

另请参阅Mozilla's documentation更多示例