php - 如何使用 json_encode 调用 PHP 中的多个类？

Question

谁能帮我解决这个问题吗？我正在尝试在此文件中调用我的类(all-function.php)

class rating_star{
        function loop_star($rating){
            ......
        }
}

我在searching-data.php中调用这个类

 $que1_search = mysql_query("SELECT p.id AS id,pd.name AS nama,pd.price AS
 harga,pd.stock as stok,pd.rating AS rating, pd.rater AS rater,pdisc.discount 
AS disc, pi.image AS imgnya,t.tags AS tagnya FROM product p,product_detail 
pd,product_discount pdisc,product_image PI,tags t WHERE p.id=pd.id_product AND 
p.id=pdisc.id_product AND p.id=pi.id_product AND p.id=t.id_product AND pd.name 
LIKE'%$_COOKIE[cari_data]%' GROUP BY p.tanggal DESC");


    while ($data_que1_search = mysql_fetch_array($que1_search)) {
        include "../../_plugin/_config/all-function.php";
        echo "
        <li style='margin-top:10px;'>
        <div id='img-search' style='border-bottom:2px solid #3b3b3b;height:270px'>
            <img src='../../_img/_barang/$data_que1_search[imgnya]' height='250px' style='margin:10px 0px'>
        </div>
        <div id='ket-search' class='c-back-grey'>
            <p class='c-f-left c-text-a-left c-bold'>$data_que1_search[nama]</p>
            <p class='c-f-left c-text-a-left c-color-pink c-bold' style='width:280px;margin-bottom:10px;'>Rp. $data_que1_search[harga],00</p>
            <div id='for-star-1' style='margin:5px 0px 10px -65px;'>";
            $rate = $data_que1_search['rating']/$data_que1_search['rater'];

          $call_f_star = new rating_star;

          $call_f_star->loop_star($rate);

            echo "
                <p class='c-font-12 c-color-dark' style='margin-top:-3px'> Rating : ".$rate."</p>
            </div>
            <p class='c-f-left c-text-a-left c-color-dark-blue c-bold' style='margin-top:10px;width:280px'>$data_que1_search[stok]</p>
             <div class='c-clean'></div>
            </div>
            <div class='c-clean'></div>
       </li>
        ";
    }

错误表明

Fatal error: Cannot redeclare class rating_star in C:\wamp\www\POKOKO_plugin_config\all-function.php on line 5

我听说我可以在这种情况下使用json_encode，但直到现在我仍然无法理解json_encode。有人可以帮我修复我的项目吗？

谢谢。

Answer 1

在 PHP 中包含一个文件来运行脚本。由于您的脚本定义了一个类，因此如果多次包含它，您将尝试重新定义该类。为了确保您的脚本只执行一次:

include_once "../../_plugin/_config/all-function.php";

但更好的是，不要在循环中包含文件。最佳做法是在脚本顶部包含一次。