javascript - 我对几行代码 AngularJS 有一些疑问

Question

在我工作的地方，我们有一个需要修改的 angularjs 项目，但我无法完全理解这段代码:

app.controller("complementsController", function($scope, $rootScope, $mdSidenav, $timeout, $localStorage, $window) {
    $scope.storage = $localStorage;
    $scope.arrayCubiert = $scope.storage.cocinaCubiert.split("-");
    $scope.tipoCubiert = $scope.arrayCubiert[1];
    $scope.return = function() {
        $window.history.back()
    };
    $scope.configurations = [{
        logo: "some-logo",
        val: 1
    }];
    "CUE" != $scope.tipoCubiera && "CUF" != $scope.tipoCubiert && "CUS" != $scope.tipoCubiert || $scope.configurations.push({
        logo: "fiss-logo",
        val: 2
    });
    "CUE" == $scope.tipoCubiert && $scope.configurations.push({
        logo: "grafett-essence",
        val: 3
    });
    $scope.opcionTitle = "EhapeAL", $scope.opcionImg = [ ["EAL.png", "EhapeAL AL"] ];
    $scope.opcionBtn = 1, $timeout(function() {
        $mdSidenav("sidebar").toggle().then(function() {})
    }, 500);

具体我不明白的是:

"CUE"!= $scope.tipoCubierta && "CUF"!= $scope.tipoCubierta && "CUS"!= $scope.tipoCubierta || $scope.configuraciones.push({ 标志:“菲索标志”， 值:2 }),

这是一种简写条件？？？如果是这样，就可以用“传统”方式制成。

Answer 1

来自 MDN 关于 logical opereator :

Short-circuit evaluation

As logical expressions are evaluated left to right, they are testedfor possible "short-circuit" evaluation using the following rules:

false && anything is short-circuit evaluated to false.

true || anything is short-circuit evaluated to true.

The rules of logic guarantee that these evaluations are always correct. Note that theanything part of the above expressions is not evaluated, so any sideeffects of doing so do not take effect.

所以上述代码的“传统”方式是:

if(!("CUE" != $scope.tipoCubierta && "CUF" != $scope.tipoCubierta && "CUS" != $scope.tipoCubierta)){
     $scope.configuraciones.push({ logo: "fisso-logo", val: 2 })
}