javascript - 扩展 Angular 服务/工厂以获取日期数组和整数数组，并创建一个包含键值对的数组

Question

我有一个服务/工厂，它接受日期数组，并根据 ISO 周将其分组到数组 [[],[]] 中。此功能按预期工作。

但是我如何扩展服务/工厂以获取另一个值数组(只是普通整数值)，并为每个日期和值创建一个键值对。仍然是数组数组的相同输出格式？

这是我的服务/工厂电话:

$scope.weeks = GroupDateRangeService.createArray(timeline_data, time_trend);

传递给服务的数据如下所示:

timeline_data: ["2017-01-04","2017-01-05","2017-01-06","2017-01-07","2017-01-08","2017-01-09","2017-01-10","2017-01-11"]

time_trend: [566, 607, 430, 357, 277, 591, 711, 206]

结果看起来像这样:

result: [["2017-01-04": 566,"2017-01-05": 607,"2017-01-06": 430,"2017-01-07": 357,"2017-01-08": 277], ["2017-01-09": 591,"2017-01-10": 711,"2017-01-11": 206]]

这是我的服务/工厂:

(function () {
    'use strict';

    angular
        .module('portalDashboardApp')
        .factory('GroupDateRangeService', GroupDateRangeService);

    GroupDateRangeService.$inject = [];

    function GroupDateRangeService() {

        var service = {
            createArray: createArray,
        };

        return service;

        function createArray(data) {
            var arr = data.map(function (s) {
                var week = getWeekNumber(parseISOLocal(s));
                return week[0] + ('0' + week[1]).slice(-2) + ':' + s;
            }).sort();
            return createGroupedArray(createGroupObject(arr));
        };

        function createGroupObject(arr) {

            var groupedObj = arr.reduce(function (result, value) {

                var b = value.split(':');

                if (!result[b[0]]) result[b[0]] = [];
                result[b[0]].push(b[1]);

                return result;

            }, {});

            return groupedObj;
        };

        function createGroupedArray(groupedObj) {

            // Grab arrays in order of week number. Sort keys to maintain order
            var groupedArray = Object.keys(groupedObj).sort().map(key=>groupedObj[key]);

            return groupedArray;
        }

        /* Helper to get the ISO week number of a date
        ** @param {Date} date to get week of
        ** @returns {Array} [year, weekNumber]
        */
        function getWeekNumber(d) {
            d = new Date(+d);
            d.setHours(0, 0, 0, 0);
            d.setDate(d.getDate() + 4 - (d.getDay() || 7));
            var yearStart = new Date(d.getFullYear(), 0, 1);
            var weekNo = Math.ceil((((d - yearStart) / 86400000) + 1) / 7);
            return [d.getFullYear(), weekNo];
        }

        /* Parse ISO 8601 format date string to local date
        ** @param {string} s - string to parse like 2016-12-15
        ** @returns {Date}
        */
        function parseISOLocal(s) {
            var b = s.split(/\D/);
            return new Date(b[0], b[1] - 1, b[2]);
        }
    }

})();

非常感谢您的指导!

Answer 1

你的结果不能像那样，数组不能有键值对。它必须是对象数组的数组。如果重构函数以接受第二个参数，则可以执行以下操作:

function createArray(data, optionalTimeTrend) {
    var arr = data.map(function (s) {
        var week = getWeekNumber(parseISOLocal(s));
        return week[0] + ('0' + week[1]).slice(-2) + ':' + s;
    }).sort();
    var results = createGroupedArray(createGroupObject(arr));
    if (optionalTimeTrend && optionalTimeTrend.length === data.length) {
        for (var i = 0; i < results.length; i++) {
            results[i] = results[i].map(function (date, index) {
                var obj = {};
                obj[date] = optionalTimeTrend[index];
                return obj;
            });
        }
    }
    return results;
};

你的结果应该是这样的:

result: [[{"2017-01-04": 566},{"2017-01-05": 607},{"2017-01-06": 430},{"2017-01-07": 357},{"2017-01-08": 277}], [{"2017-01-09": 591},{"2017-01-10": 711},{"2017-01-11": 206}]]