php - 更新时 SQL 语法错误

Question

我正在尝试为用户设置一种设置方式，我将设置以 json 格式保存在数据库中。当我尝试更新用户时，出现以下语法错误:

Warning: PDOStatement::execute(): SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ''settings' = '{\"background-color\":\"050505\"}' WHERE ID = '2'' at line 1 in C:...\htdocs\app\model\model.database.php on line 29

这是我的代码。

public function setColor(){
    $modUser = $this->model('user');
    $modInput = $this->model('input');
    $modViewData = $this->model('viewData');
    $modUser->setSetting("background-color",str_replace('#', "", $modInput->returnPost("color")));
    $this->view('profile/view.profile', $modViewData->getData());
}
//in User model
public function setSetting($name, $value){
    $settings = $this->getSetting();
    $settings[$name] = $value;
    $settings = json_encode($settings);
    $this->update("settings", $settings);
}
public function update($field, $value){
    $sql = "UPDATE `users` SET :field = :value WHERE `ID` = :id";
    $params = [":field" => $field, ":value" => $value, ":id" => $this->_data->ID];
    $database = $this->model('database');
    $database->query($sql,$params);
}

Answer 1

您无法参数化表名和列名。您需要将它们直接插入到查询字符串中。一种方法是:

$sql = "UPDATE `users` SET $field = :value WHERE `ID` = :id";