javascript - 如何使用 xPath 选择多个元素？

Question

我正在使用 defiantjs选择对象中的元素。这是我的对象:

{
 "name": "Retail Sales",
 "weight": 10,
 "length": 6,
 "type": "retailSales",
 "rows": [
  {
     "dealerEvaluationHistoryID": 0,
     "performanceDealerMappingDetailID": 14,
     "month": 1,
     "plan": 0,
     "actual": 0,
     "weight": 0,
     "pelanggaranWilayah": 0
  },
  {
     "dealerEvaluationHistoryID": 0,
     "performanceDealerMappingDetailID": 14,
     "month": 2,
     "plan": 0,
     "actual": 0,
     "weight": 0,
     "pelanggaranWilayah": 0
  },
  {
     "dealerEvaluationHistoryID": 0,
     "performanceDealerMappingDetailID": 14,
     "month": 3,
     "plan": 0,
     "actual": 0,
     "weight": 0,
     "pelanggaranWilayah": 0
  }
 ]
}

如何选择行[]中每个对象内的所有月份、计划、实际和重量？我想要这样的输出:

[[1,0,0,0],[2,0,0,0],[3,0,0,0]]

我可以做 //rows/month 和 //rows/plan 但不知道如何做。

Answer 1

您可以使用 map 方法为数组中的每个项目应用一个回调函数。

阅读更多关于 map 的信息方法。

let obj={
   "name": "Retail Sales",
   "weight": 10,
   "length": 6,
   "type": "retailSales",
   "rows": [
      {
         "dealerEvaluationHistoryID": 0,
         "performanceDealerMappingDetailID": 14,
         "month": 1,
         "plan": 0,
         "actual": 0,
         "weight": 0,
         "pelanggaranWilayah": 0
      },
      {
         "dealerEvaluationHistoryID": 0,
         "performanceDealerMappingDetailID": 14,
         "month": 2,
         "plan": 0,
         "actual": 0,
         "weight": 0,
         "pelanggaranWilayah": 0
      },
      {
         "dealerEvaluationHistoryID": 0,
         "performanceDealerMappingDetailID": 14,
         "month": 3,
         "plan": 0,
         "actual": 0,
         "weight": 0,
         "pelanggaranWilayah": 0
      }
   ]
}
let array=obj.rows.map(function(row){
  return [row.month,row.plan,row.actual,row.weight];
});
console.log(JSON.stringify(array));