gpt4 book ai didi

MySQL : SELECT all users with 5 unopened messages in there last 5 messages received in a messages table

转载 作者:行者123 更新时间:2023-11-29 21:02:58 26 4
gpt4 key购买 nike

我使用的是mysql。

我有一个包含 userid、message_id、opened(true 或 false)、时间戳的消息表。

我希望所有未打开最近收到的 5 条消息的用户

这就是我现在拥有的:

SELECT mnc.userid
FROM `messages` mnc
WHERE (select count(*) from messagesas m where m.userid = mnc.userid
and m.message_sendtime_timestamp >= mnc.message_sendtime_timestamp
and m.opened = 'FALSE') >= 6

但是,这给了我超过 6 条未打开消息的用户不一定是连续的

这里是示例数据

CREATE TABLE messages
(`user_id` int, `timestamp` datetime, `opened` varchar(5))
;

INSERT INTO messages
(`user_id`, `timestamp`, `opened`)
VALUES
(1, '2016-01-01 00:00:00', 'false'),
(1, '2016-02-01 00:00:00', 'false'),
(1, '2016-03-01 00:00:00', 'false'),
(1, '2016-04-01 00:00:00', 'false'),
(1, '2016-05-01 00:00:00', 'false'),
(1, '2016-06-01 00:00:00', 'false'),
(2, '2016-01-01 00:00:00', 'false'),
(2, '2016-02-01 00:00:00', 'false'),
(2, '2016-03-01 00:00:00', 'false'),
(3, '2015-01-01 00:00:00', 'false'),
(3, '2016-01-01 00:00:00', 'false'),
(3, '2016-02-01 00:00:00', 'false'),
(3, '2016-03-01 00:00:00', 'false'),
(3, '2016-04-01 00:00:00', 'false'),
(3, '2016-05-01 00:00:00', 'true'),
(3, '2016-06-01 00:00:00', 'false'),
(4, '2015-01-01 00:00:00', 'true'),
(4, '2015-02-01 00:00:00', 'true'),
(4, '2016-01-01 00:00:00', 'false'),
(4, '2016-02-01 00:00:00', 'false'),
(4, '2016-03-01 00:00:00', 'false'),
(4, '2016-04-01 00:00:00', 'false'),
(4, '2016-05-01 00:00:00', 'false'),
(4, '2016-06-01 00:00:00', 'false')

预期结果:

userid 
1
4

最佳答案

回答这个问题

我想要所有在最近收到的 5 条消息中未打开消息的用户吗?

首先,您需要为每个user_id创建一个row_id

SELECT @rowid := IF(@prev_value = user_id,  @rowid + 1,  1) as row_id,
m.*
@prev_value := user_id
FROM messages m,
(SELECT @row_num := 1) x,
(SELECT @prev_value := '') y
ORDER BY `timestamp` DESC

然后检查该子查询有多少条打开的消息

<强> SQL Fiddle Demo

SELECT user_id, COUNT(*), SUM(opened = 'false')
FROM (
SELECT @rowid := IF(@prev_value = user_id, @rowid + 1, 1) as row_id,
m.*,
@prev_value := user_id
FROM messages m,
(SELECT @row_num := 1) x,
(SELECT @prev_value := '') y
ORDER BY user_id, `timestamp` DESC
) T
WHERE row_id <= 5 -- only check last 5 or less messages
GROUP BY user_id
HAVING COUNT(*) = SUM(opened = 'false') -- Check all messages are NOT opened

关于MySQL : SELECT all users with 5 unopened messages in there last 5 messages received in a messages table,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37054750/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com