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android - 单击 gridview 中的项目时尝试获取 _id 获取强制转换异常

转载 作者:行者123 更新时间:2023-11-29 20:58:40 27 4
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当单击我的 GridView 中的项目时,我试图从光标中获取 _id 字段,相同的代码在 ListView 中工作正常但在这里似乎不起作用:

类(class):

CurAdapter Cur;
GridView grid;

创建时:

Cursor mCur = dbHelper.contactsQuery(); 
grid = (GridView)rootView.findViewById(R.id.gridview);
Cur = new CurAdapter(getActivity(), mCur,0);
grid.setAdapter(Cur);
grid.setTextFilterEnabled(true);

点击:

grid.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,int position, long id) {

System.out.println(position);
System.out.println(id);

Cursor cursor = (Cursor) grid.getItemAtPosition(position);

}
});

我的自定义适配器:

private class CurAdapter extends CursorAdapter{

public CurAdapter(Context context, Cursor c, int flags) {

super(context, c, flags);

}



@Override
public void bindView(View view, Context context, Cursor cursor) {

TextView tv = (TextView) view.findViewById(R.id.item_text);
tv.setTypeface(helv_light);
final RoundedImageView iv = (RoundedImageView) view.findViewById(R.id.item_image);

String name = (cursor.getString(cursor.getColumnIndexOrThrow("Name")));
image = cursor.getString(cursor.getColumnIndexOrThrow("imageUri"));
String isAdhoc = (cursor.getString(cursor.getColumnIndexOrThrow("isAdhoc")));

if(isAdhoc.equals("1")){
boolean check = false;
String frName = null;
Cursor mCur = dbHelper.friendsName(name);
if(mCur != null && mCur.moveToFirst()){
do{
frName = mCur.getString(mCur.getColumnIndex("FriendsName"));
if(frName != null){


if(frName.equalsIgnoreCase(selfName)){
check = false;
}else {

check = true;


}


}

}while (mCur.moveToNext());
}

if(check){
name = name+" "+"("+frName+"'s"+" pet)";
}

}


tv.setText(name);


if((image.contains("jpg") || image.contains("png")) && image.contains("adhoc") != true){

image = "file://"+image;

}

final DisplayImageOptions options = new DisplayImageOptions.Builder()
.showImageOnLoading(R.drawable.icon_default)
.showImageForEmptyUri(R.drawable.icon_default)
.showImageOnFail(R.drawable.icon_default)
.resetViewBeforeLoading(true)
.cacheInMemory(true) // default
.cacheOnDisk(true) // default
.build();

ImageLoader.getInstance().displayImage(image, iv, options);

}
@Override
public View newView(Context context, Cursor cursor, ViewGroup parent) {

View view = LayoutInflater.from(context).inflate(R.layout.grid_layout, null);

return view;

}


public long getItemId(int position) {

return position;
}

public Object getItem(int position) {
return position;
}

}

我的问题:

11-10 14:51:47.989: E/AndroidRuntime(11194): java.lang.ClassCastException: java.lang.Integer cannot be cast to android.database.Cursor
11-10 14:51:47.989: E/AndroidRuntime(11194): at com.example.FragmentTab3$1.onItemClick(FragmentTab3.java:125)

最佳答案

你得到 ClassCastException 因为你覆盖了 getItem

 public Object getItem(int position) {
return position;
}

在您的情况下,它返回的是 int 而不是光标。您可以删除它并使用 getItem 的父实现(它应该返回位置处的 Cursor)

关于android - 单击 gridview 中的项目时尝试获取 _id 获取强制转换异常,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26840380/

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