gpt4 book ai didi

mysql - 在SQL中计算每个测量值的成功百分比

转载 作者:行者123 更新时间:2023-11-29 20:29:16 25 4
gpt4 key购买 nike

我有 3 个数据库表,示例数据如下

Meas_id - integer(Foreign keyed to Measurement.meas_id)    
Tool_id - integer(Foreign keyed to Events.Machine_id)
Processdate- Timestamp with timezone (UTC)
CreatedDate- Timestamp with timezone (UTC)

阅读

   Meas_id Tool_id    Status         Processdate
1 13 Completed 2016-01-01 01:34:11
1 28 Failed 2016-01-01 08:37:11
1 54 Failed 2016-01-02 16:04:12
1 32 Completed 2016-01-04 07:13:11
1 39 Completed 2016-01-04 14:14:14
1 12 Completed 2016-01-05 22:10:09
1 9 Completed 2015-12-28 13:11:07
1 17 Completed 2016-01-25 13:14:11
1 27 Completed 2016-01-15 14:15:16
1 31 Failed 2016-01-07 16:08:04
2 113 Completed 2016-01-01 01:34:11
2 128 Failed 2016-01-01 08:37:11
2 154 Failed 2016-01-02 16:04:12
2 132 Completed 2016-01-04 07:13:11
2 139 Completed 2016-01-04 14:14:14
2 112 Completed 2016-01-05 22:10:09
2 90 Completed 2015-12-28 13:11:07
2 117 Completed 2016-01-25 13:14:11
2 127 Completed 2016-01-15 14:15:16
2 131 Failed 2016-01-07 16:08:04

事件

   Meas_id Machine_id Event_Name         CreatedDate
1 13 Success 2015-12-27 01:34:11
1 17 Error 2015-12-27 08:37:11
1 28 Success 2015-12-27 16:04:12
1 9 Success 2015-12-28 07:13:11
1 54 Success 2015-12-28 14:14:14
1 31 Error 2015-12-28 22:10:09
1 32 Success 2015-12-29 13:11:07
1 39 Success 2015-12-29 13:14:11
1 12 Success 2015-12-31 14:15:16
1 27 Success 2016-01-01 16:08:04
2 113 Success 2015-12-27 01:34:11
2 117 Error 2015-12-27 08:37:11
2 128 Success 2015-12-27 16:04:12
2 90 Success 2015-12-28 07:13:11
2 154 Success 2015-12-28 14:14:14
2 131 Error 2015-12-28 22:10:09
2 132 Success 2015-12-29 13:11:07
2 139 Success 2015-12-29 13:14:11
2 112 Success 2015-12-31 14:15:16
2 127 Success 2016-01-01 16:08:04

测量

  Meas_id Meas_name
1 Length
2 Breadth

对于每个测量“长度”和“宽度”以及一周中的每一天,我尝试计算 2016 年第一周自创建日期起 168 小时内完成的所有工具/机器测量的成功百分比.

我想要的输出是

   Measurement DayofTheWeek PercentageSuccess
Length 1 50
Length 2 0
Length 3 0
Length 4 100
Length 5 100
Length 6 0
Length 7 0
Breadth 1 50
Breadth 2 0
Breadth 3 0
Breadth 4 100
Breadth 5 100
Breadth 6 0
Breadth 7 0

我尝试这样做,但肯定缺少一些逻辑并且它不起作用。

Select m.Meas_name, 
datepart(dd, Processdate) as DayofTheWeek,
(Count(m.Meas_name)* 100 / (Select Count(Event_Name) From Events where Event_Name = 'Success')) as PercentageSuccess

FROM Readings r JOIN
Measurements m
ON r.Meas_id = m.Meas_id
JOIN Events e
ON e.Meas_id = m.Meas_id
WHERE m.Meas_name IN ('Length', 'Breadth') AND
r.Status = 'Completed' AND
e.CreatedDate >= DATEADD(hh, -168, GETDATE())
GROUP BY m.Meas_name, datepart(dd, Processdate);

请提供有关实现该目标的优化方法的意见。

最佳答案

很好,我的正确答案被否决了,可能是因为我的答案不是很清楚,有点难以解释,所以这里是针对您的评论和否决者(我认为他们只是在报复)的编辑。

无论如何,您在有效时加入 3 个表会复制事件表中的数据。因此,您计算记录的方式总是会被夸大且不正确。您对百分比的计算也恰好是倒退的。

在连接上,您似乎缺少在连接中使用 Tool_id 。您可以尝试如下操作:

SELECT
m.Meas_name
,DAYOFWEEK(r.ProcessDate) as DayOfTheWeek
,(COUNT(CASE WHEN e.Event_Name = 'Success' tHEN e.Meas_id END)/(COUNT(e.Meas_id) * 1.0)) * 100 as PercentageSuccess
FROM
Measurements m
INNER JOIN Events e
ON m.Meas_id = e.Meas_id
INNER JOIN Readings r
ON e.Meas_id = r.Meas_id
AND e.Machine_id = r.Tool_id
AND r.Status = 'Completed'
AND r.ProcessDate BETWEEN '2016-01-01' AND '2016-01-07'
WHERE
m.Meas_name IN ('Length','Breadth')
GROUP BY
m.Meas_name
,DAYOFWEEK(r.ProcessDate)

请注意,这是为 mysql 编写的,因为这是您帖子中标记的内容。如果您确实想要按照语法建议使用 sql-server,请告诉我。另外,我猜测您确实想按 processdate 进行过滤,但如果您想按 Event.CreateDate 进行过滤,则将其置于事件连接的 ON 条件中。

关于mysql - 在SQL中计算每个测量值的成功百分比,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39155876/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com