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javascript - 超时才能再次点击

转载 作者:行者123 更新时间:2023-11-29 20:05:24 25 4
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在我的拼写游戏中,用户点击字母来拼写单词。当点击一个字母时,它会动画到正确的区域。

问题是当您单击它们以快速播放时,动画困惑并且字母重叠。

为了解决这个问题,我想在再次点击可点击对象之前添加 1 或 2 秒的超时。

我该怎么做,我应该把它放在我的代码中的什么地方?

这是可点击的代码

$('.drag').on('click', function(e) {
e.preventDefault();

var target = $('.drop-box.spellword:not(.occupied):first');
var targetPos = target.position();
var currentPos = $(this).offset();
var b = $(this);

if (target.length) {
target.addClass("occupied");
$(".minibutton").prop("disabled", true);
b.clone().addClass(
b.data("letter") == target.data("letter") ? "wordglow3" : "wordglow").appendTo("table").css({
background: "transparent",
position: "absolute",
top: currentPos.top,
left: currentPos.left
}).animate({
top: targetPos.top,
left: targetPos.left
}, "slow", function() {
$(this).css({
top: 0,
left: 0
}).appendTo(target);
if (!$('.drop-box.spellword:not(.occupied)').length) {
var wordIsCorrect = 0;
$('.drop-box.spellword').each(function() {
if ($(this).attr("data-letter") == $(this).find("div").attr("data-letter")) {
wordIsCorrect++;
}
});
console.log(wordIsCorrect);
console.log($('.drop-box.spellword').length);
if ($('.drop-box.spellword').length == wordIsCorrect) {

$('.drop-box.spellword').addClass('wordglow2');
$(right).val('Well Done!');
$(right).show();
audioS.play();
$('.counter').html(completeWords + '/6').show();
$(wrong).hide();
$('.minibutton').prop('disabled', false);

} else {

$('.drop-box.spellword').addClass("wordglow4").css('color', 'transparent');
$(wrong).val('Try Again');
$('.minibutton').prop('disabled');
$(wrong).show();
audioF.play();
$('.counter').html(completeWords + '/6').show();
$(right).hide();
//$('.minibutton').prop('disabled', true);
$('.drop-box.spellword').animate({
'opacity': 1
}, 1000, function() {
$(this).removeClass('wordglow4').removeClass('occupied').html('')
});
}


}
});

}

谢谢!

最佳答案

var animation = false;
$('.drag').on('click', function(e) {
if(animation) return;
animation = true;

并添加到您的回调中:

animation = false;

全文:

var animation = false;

$('.drag').on('click', function(e) {
e.preventDefault();
if(animation) return;
animation = true;
setTimeout(function(){animation = false;},1000); // Can't click letters for 1 sec

var target = $('.drop-box.spellword:not(.occupied):first');
var targetPos = target.position();
var currentPos = $(this).offset();
var b = $(this);

if (target.length) {
target.addClass("occupied");
$(".minibutton").prop("disabled", true);
b.clone().addClass(
b.data("letter") == target.data("letter") ? "wordglow3" : "wordglow").appendTo("table").css({
background: "transparent",
position: "absolute",
top: currentPos.top,
left: currentPos.left
}).animate({
top: targetPos.top,
left: targetPos.left
}, "slow", function() {
$(this).css({
top: 0,
left: 0
}).appendTo(target);
if (!$('.drop-box.spellword:not(.occupied)').length) {
var wordIsCorrect = 0;
$('.drop-box.spellword').each(function() {
if ($(this).attr("data-letter") == $(this).find("div").attr("data-letter")) {
wordIsCorrect++;
}
});
console.log(wordIsCorrect);
console.log($('.drop-box.spellword').length);
if ($('.drop-box.spellword').length == wordIsCorrect) {

$('.drop-box.spellword').addClass('wordglow2');
$(right).val('Well Done!');
$(right).show();
audioS.play();
$('.counter').html(completeWords + '/6').show();
$(wrong).hide();
$('.minibutton').prop('disabled', false);

} else {

$('.drop-box.spellword').addClass("wordglow4").css('color', 'transparent');
$(wrong).val('Try Again');
$('.minibutton').prop('disabled');
$(wrong).show();
audioF.play();
$('.counter').html(completeWords + '/6').show();
$(right).hide();
//$('.minibutton').prop('disabled', true);
$('.drop-box.spellword').animate({
'opacity': 1
}, 1000, function() {
$(this).removeClass('wordglow4').removeClass('occupied').html('')
});
}


}
}, function(){
animation = false;
});

}

在那里我使用了 setTimeout 而不是回调。

关于javascript - 超时才能再次点击,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12194648/

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