android - 通过 Intent 将编辑文本的文本移动到另一个 Activity 会引发异常

Question

我正在尝试在我的 Android 应用程序中实现搜索功能，我想从 Activity Discover 获取用户在搜索编辑文本中编写的内容，并打开一个名为 Activity search 的新 Activity，其中可以显示结果，发布object 是我实现的一个类，我在其中从后端获取数据每次我尝试都会抛出异常这是我这部分的 Activity 发现代码 `

search.addTextChangedListener(new TextWatcher() {
            @Override
            public void beforeTextChanged(CharSequence s, int start, int count, int after) {

            }

        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {

        }

        @Override
        public void afterTextChanged(Editable s) {
            // setContentView(R.layout.search_grid);
            // gridView2 = (GridView) findViewById(R.id.search_grid);
            RequestParams rp = new RequestParams();
            final String url;
            if (people.isChecked()) {
                rp.add("user", search.getText().toString());
                rp.add("counter", "");
                url = "search_users";
            } else if (tags.isChecked()) {
                rp.add("tag", search.getText().toString());
                rp.add("counter", "");
                url = "search_exact_hashtag";
            } else {
                rp.add("location", search.getText().toString());
                rp.add("counter", "");
                url = "search_location";
            }
            final ArrayList<PostObject> addyExtras = new ArrayList<>();
            //Toast.makeText(getApplicationContext()," something " + , Toast.LENGTH_SHORT).show();
            PabloClient.post(url, rp, new JSONHandler(getApplicationContext(), new JSONHandler.OnFinishedListener() {
                @Override
                public void OnFinished(int statusCode, Header[] headers, JSONObject response, int result) {
                    try {
                        if (result == 1) {
                            // Toast.makeText(getApplicationContext(), response.toString(), Toast.LENGTH_SHORT).show();

                            JSONArray posts = response.getJSONArray("data");
                            setContentView(R.layout.search_grid);
                            //////////////////////////////////////////////


                            //////////////////////////////////////////////////////////////////
                            for (int i = 0; i < posts.length(); i++) {
                                searchPosts.add(new PostObject(posts.getJSONObject(i)));


                                addyExtras.add(searchPosts.get(i));

                            }




                        }
                    } catch (JSONException e) {
                        e.printStackTrace();

                    }
                    Intent intent = new Intent(ActivityDiscover.this, ActivitySearch.class);
                    intent.putParcelableArrayListExtra("mylist", addyExtras);
                    startActivity(intent);

                }
            }));
        }

    });

`

这里是我如何获得搜索 Activity 的 Intent

searchPosts2 = getIntent().getParcelableArrayExtra("mylist");


Answer 1

数组应该在 Bundle 的帮助下传递

发送数组

首先从发送方需要在包中添加数组列表

Bundle data = new Bundle();
data.putParcelableArrayList("mylist", addyExtras);

然后将 bundle 添加到 Intent

 Intent intent = new Intent(ActivityDiscover.this, ActivitySearch.class);
    intent .putExtra("content", data);
    startActivity(yourIntent);

检索数组

在接收端从 Intent 中获取包

Bundle data =  getIntent().getBundleExtra("content");

然后从包中获取数组列表

searchPosts2  =  data.getParcelableArrayList("mylist");