gpt4 book ai didi

php编码使用php将表单提交到服务器

转载 作者:行者123 更新时间:2023-11-29 19:45:36 28 4
gpt4 key购买 nike

我使用 php 和 mysql 键入了此代码。在 If 语句中,条件 Id 部分未插入数据库。但其他字段被插入到数据库中。我无法找出错误。谁能告诉我错误是什么?

<?php
$conn=mysqli_connect("localhost","root","database","user") or die("unable to connect");
//echo "Connected Successfully";
?>
<h2>Form Submission to Server</h2>
<?php
if(isset($_POST["submit"]))
{// get user inputs

$error="";
$resultmessage="";
$id=$_POST["id"];
$firstname=$_POST["firstname"];
$lastname=$_POST["lastname"];
$email=$_POST["email"];
$password=$_POST["password"];
//error messages
$missingfirstname="<p>Enter your First name</p>";
$missinglastname="<p>Enter your Last name</p>";
$missingemail="<p>Enter your Email id</p>";
$invalidmail="<p>enter your valid mail id</p>";
$missingpwd="<p>Enter your password</p>";
if(!$firstname)
{
$error.=$missingfirstname;
}
else
{
$firstname=filter_var($firstname,FILTER_SANITIZE_STRING);
}
if(!$lastname)
{
$error.=$missinglastname;
}
else
{
$lastname=filter_var($lastname,FILTER_SANITIZE_STRING);
}

if(!$email)
{
$error.=$missingemail;
}
else
{
$email=filter_var($email,FILTER_SANITIZE_EMAIL);
if(!filter_var($email,FILTER_VALIDATE_EMAIL))
{
$error.=$invalidmail;
}
}
if(!$password)
{
$error.=$missingpwd;
}
if($error)
{
$resultmessage='<div class="alert alert-danger">'.$error.'</div>';

echo $resultmessage;
}

else
{
//no errors,prepare variables for query
$tblname="attend4";
$firstname=mysqli_real_escape_string($conn,$firstname);
$lastname=mysqli_real_escape_string($conn,$lastname);
$email=mysqli_real_escape_string($conn,$email);
$password=mysqli_real_escape_string($conn,$password);
$password=md5($password);

//execute the query
if(!$id)
{
$sql="INSERT INTO attend4(firstname,lastname,email,password)VALUES('$firstname','$lastname','$email','$password')";
}
else
{
$sql="INSERT INTO attend4(id,firstname,lastname,email,password)VALUES('$id',$firstname','$lastname','$email','$password')";

} if(mysqli_query($conn,$sql))
{
$resultmessage="Data added successfully";
echo $resultmessage;
}

else
{
$resultmessage="unable to add";
echo $resultmessage;
}

}

}

?>
<form action="33.populateusigform.php" method="post">

<div class="form-group">
<label for="number">Number</label>
<input type="number" name="id" id="id" class="form-control" maxlength="4" placeholder="Enter your Number">
</div>
<div class="form-group">
<label for="firstname">First Name</label>
<input type="text" name="firstname" id="firstname" maxlength="30" class="form-control" placeholder="Enter your Firstname">

</div>
<div class="form-group">
<label for="lastname">Lastname</label>
<input type="text" name="lastname" id="lastname" maxlength="30" placeholder="Enter your lastname" class="form-control">
</div>
<div class="form-group">
<label for="email">Email</label>
<input type="email" name="email" id="email" maxlength="30" placeholder="Enter your Email Id"class="form-control">
</div>
<div class="form-group">
<label for="password">Password</label>
<input type="password" name="password" maxlength="30" placeholder="Enter your Password" class="form-control">
</div>

<input type="submit" name="submit" class="btn btn-success center-block" value="Send data">

</form>

最佳答案

我怀疑您的问题出在 if($id) 上,如果给定 0,它可能会表现得很奇怪,从而触发没有 id 术语的 sql 查询。

我会使用 if(empty($id)) 相反,它会更可靠。

关于php编码使用php将表单提交到服务器,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41011884/

28 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com