gpt4 book ai didi

php - 如何从mysql显示平均值

转载 作者:行者123 更新时间:2023-11-29 19:45:24 25 4
gpt4 key购买 nike

如何显示mysql中某一列的平均值?

下面是我迄今为止尝试过的代码:

<?php
if (isset($_GET["age"]));
$age = ($_GET["age"]);
include($_SERVER["DOCUMENT_ROOT"] . "/includes/config.php");

// Input
$sql = "SELECT AVG(column_name) FROM table_name";

// Check age
if ($age > 99 or $age < 5) {
echo ("We only store data of people between the age of 5 and 99.");
if (!mysqli_query($conn, $sql)) {
die('Error: ' . ((is_object($GLOBALS["___mysqli_ston"])) ? mysqli_error($GLOBALS["___mysqli_ston"]) : (($___mysqli_res = mysqli_connect_error()) ? $___mysqli_res : false)));
}
}
else {
echo ("We got it!");
}

// Close connection
((is_null($___mysqli_res = mysqli_close($conn))) ? false : $___mysqli_res);

die();
?>

但是如何精确地为 AVG 结果定义一个最多保留 2 位小数的变量呢?

我想使用它并将其显示到另一个文件中(所以我将包含这个文件)。

我现在拥有的

<?php
if (isset($_GET["age"]));
$age = ($_GET["age"]);
include($_SERVER["DOCUMENT_ROOT"] . "/3/includes/config.php");
include($_SERVER["DOCUMENT_ROOT"] . "/3/includes/opendb.php");

// My own created code
$sql = $conn->query("SELECT ROUND(AVG(price AS FLOAT), 2) FROM data WHERE age= '$age'");
$data = $sql->mysqli_fetch_assoc();
$avg_data = $data['price'];
echo $avg_data;

// This below is from an other post but don't know how it works and if it is good.
$ratings = $conn->query("SELECT AVG(price) avg_rating FROM data form_id = '" . $age . "'");
$data2 = $ratings->mysqli_fetch_assoc();
$avg_rating = $data2['avg_rating'];
echo $avg_rating;

die();

?>

最佳答案

像这样使用以获得带有两位小数的平均值。

  $sql = "SELECT ROUND(AVG(column_name AS FLOAT), 2) FROM table_name";

关于php - 如何从mysql显示平均值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41036324/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com