android - webmethod 不调用 firebase 通知 onMessageReceived 方法

Question

public void onMessageReceived(RemoteMessage remoteMessage) {

    try {

        String type=remoteMessage.getData().get("type");
        if(type.equals("1001")) {
            CommonClass common = new CommonClass(getApplication());
            CommonClass.MyTaskSendLog.execute(getApplicationContext(), DeviceDetails,lines);
        }            
    } catch (Exception ex) {
    }
}

此代码给出错误:

Method execute must be called from the main thread, currently inferred thread is worker

Answer 1

我想你的方法在服务中。

要访问服务中的 UI 线程(主线程)，您必须创建一个处理程序并在其中调用方法，如下所示:

if(type.equals("1001")) {
    Handler handler = new Handler(Looper.getMainLooper());
    handler.post(new Runnable() {
                  public void run() {
                          CommonClass common = new CommonClass(getApplication());
                          CommonClass.MyTaskSendLog.execute(getApplicationContext(), DeviceDetails,lines);
                  }
    });
}  

您可以在服务的onCreate 中创建Handler。