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android - 无法使用用户名和密码获取 HTTP Post 请求的 JSON 数据?

转载 作者:行者123 更新时间:2023-11-29 19:41:37 34 4
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使用 get 方法可以正常工作,但是当我尝试使用 Post 方法时,我什么也没得到。请查看我的代码,让我知道哪里或哪里做错了。
我有两个参数来传递用户名和密码。

class AsyncT extends AsyncTask<Void, Void, Void> {
@Override
protected Void doInBackground(Void... voids) {


HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://192.168.1.105:8080/api/login");

try {
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("username", "adii@adii.com"));
nameValuePairs.add(new BasicNameValuePair("password", "password"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
httppost.setHeader("content-type", "application/json; charset= utf-8");
httppost.setHeader("Accept", "application/json");
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();


} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}

try {
BufferedReader reader = null;
if (is != null) {
reader = new BufferedReader(new InputStreamReader(
//"UTF-8" "iso-8859-1"
is, "UTF-8"), 8);
}
StringBuilder sb = new StringBuilder();
String line;
if (reader != null) {
while ((line = reader.readLine()) != null) {
sb.append(line).append("\n");


}
}
if (is != null) {
is.close();

}
result = sb.toString();

Log.e("sb",result);

} catch (Exception e) {
Log.e("log_tag", "Error converting result " + e.toString());
}
return null;
}

}

最佳答案

我不知道你的代码有什么问题,但你应该试试这段代码,它在我这里工作得很好。希望对你有帮助

public String ip = "192.168.43.114";
public String port = "59397";

public HttpPost httppost;
String ServerAddress;
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();

JSONObject json = new JSONObject();

尝试在函数中实现您的任务,使其变得可重用。

public int login(String username, String password)  {
ServerAddress = "http://"+ip+":"+port+"/api/Users/Login";
Log.v("check","inLoginMethod");
try {

json = new JSONObject();
json.put("UserName", username);
json.put("PassWord", password);

AsyncTask<String, Integer, String> asynchTask;
AsynchServerConnection asc = new AsynchServerConnection();
asynchTask = asc.execute("");
String res = asynchTask.get();
Log.v("RES", res);

//res = jsonObject.toString();
//int check = Integer.parseInt(res);
Log.i("checkR", res + "here");
return res;

} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
Log.i("checkR", "Interrupted exception");
return 0;
} catch (ExecutionException e) {
// TODO Auto-generated catch block
e.printStackTrace();
Log.i("checkR", "ExecutionException");
return 0;
}
catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
Log.i("checkR", "JSONException");
Log.i("checkR", e.getMessage());
return 0;
}
}

最后是异步任务类

private class AsynchServerConnection extends
AsyncTask<String, Integer, String> {

@Override
protected void onPostExecute(String result) {
// TODO Auto-generated method stub

super.onPostExecute(result);
}

@Override
protected void onProgressUpdate(Integer... values) {
// TODO Auto-generated method stub

super.onProgressUpdate(values);
}

@Override
protected String doInBackground(String... params) {
// TODO Auto-generated method stub

String result = null;
try {
HttpClient client = new DefaultHttpClient();

HttpConnectionParams.setConnectionTimeout(client.getParams(), 3000); //Timeout Limit
HttpResponse response;


try {
HttpPost post = new HttpPost(ServerAddress);
Log.v(TAG, "server Addr: "+ServerAddress);

StringEntity se = new StringEntity( json.toString());
se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));

post.setEntity(se);
response = client.execute(post);

/*Checking response */
if(response!=null){

HttpEntity e = response.getEntity();
String r =EntityUtils.toString(e);
result = r;
Log.v("checkR", r);
}

} catch(Exception e) {
e.printStackTrace();
Log.v("check", "exception");
Log.v("check", e.getMessage());
//createDialog("Error", "Cannot Estabilish Connection");
}

return result;

} catch (Exception e) {
// TODO Auto-generated catch block

e.printStackTrace();
}
return result;
}
}

现在当你得到数据时,你需要它从 json 格式解码它,这是一个示例类和一个 DECODEJSON 函数,尝试根据你自己的要求实现它

package com.example.aimalkhan.vegegardenandroidapp;

/**
* Created by Aimal Khan on 12/28/2015.
*/

import android.util.Log;

import org.json.JSONException;
import org.json.JSONObject;

import java.util.ArrayList;
import java.util.List;

public class Users {

private static String userName;
private static String password;
private static String contactNumber;
private static String emailId;
private static String lat;
public static String longg = "";
private static String address;

public static String getPlantNames() {
return plantNames;
}

public static void setPlantNames(String plantNames) {
Users.plantNames = plantNames;
}

private static String plantNames;

public String getLongg() {
Log.v("checkR", longg + "in users class! - getting long");
return longg;
}

public void setLongg(String longg) {
Log.v("checkR", longg + "in users class! - seting long");
this.longg = longg;
}

public String getAddress() {
return address;
}

public void setAddress(String address) {
Users.address = address;
}

public String getLat() {
return lat;
}

public void setLat(String lat) {
this.lat = lat;
}

public String getEmailId() {
return emailId;
}

public void setEmailId(String emailId) {
this.emailId = emailId;
}

public String getContactNumber() {
return contactNumber;
}

public void setContactNumber(String contactNumber) {
this.contactNumber = contactNumber;
}

public String getPassword() {
return password;
}

public void setPassword(String password) {
this.password = password;
}

public String getUserName() {
Log.v("checkR", "in users class" + userName);
return userName;
}

public void setUserName(String userName) {
this.userName = userName;

}

/*var $id="";
var $type="";
var $firstName="";
var $lastName="";
var $contactNumber="";
var $emailId="";
var $address="";
*/

/* public Users(String id,String type)
{
this.id=id;
this.type=type;
}*/
public Users() {
}

public void decodeJson(JSONObject json) {
try {
userName = json.getString("userName");
setUserName(userName);
password = json.getString("userPassword");
setPassword(password);
contactNumber = json.getString("contactInfo");
setContactNumber(contactNumber);
emailId = json.getString("emailID");
Log.v("checkR", emailId + "in users class!");
setEmailId(emailId);
lat = json.getString("userLat");
setLat(lat);
longg = json.getString("userLong");
Log.v("checkR", longg + "in users class!");
address = json.getString("userAddress");
setAddress(address);
Log.v("checkR", address + "in users class!");
setLongg(longg);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}

}
public static List<String> plantsT;
public void decodeJsonUserPlants(String json) {
String[] arr;
plantsT = new ArrayList<String>();
Log.v("check123",json.toString()+" json");
try {
JSONObject jsonObject = new JSONObject(json);
arr = jsonObject.getString("plantNames").split(",");

for (int i = 0; i < arr.length; i++) {
arr[i] = arr[i].replaceAll("\"", "").replaceAll("\\[", "").replaceAll("\\]", "");
Log.v("check123",arr[i].toString()+" loop");
plantsT.add(arr[i]);
// plantsT.add(arr.toString());
}


} catch (JSONException e) {
e.printStackTrace();
}


}
}
//

如果问题仍然存在,请告诉我。

关于android - 无法使用用户名和密码获取 HTTP Post 请求的 JSON 数据?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38565978/

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