android - 改造后的 Post 方法永远不会在 OnResponse 或 OnFailure 中触发

Question

我正在尝试通过改造来检查服务器中是否存在某些数据。我的问题是从未经历过 onResponse 或 OnFailure。代码从不传入这两个方法。我在日志中没有收到任何错误。如果我调试，代码会在此处停止:call.enqueue(new Callback() 并在下一步中转到方法之外。

一些帮助将不胜感激

代码:

 ApiInterface apiService = ApiClient.getClient().create(ApiInterface.class);

        Call<User> call = apiService.smsPincodeCheck(getPhoneNuber, email);
        call.enqueue(new Callback<User>() {
            @Override
            public void onResponse(Call<User> call, Response<User> response) {
                if(response.isSuccess()){
                    Toast.makeText(RegisterThreeActivity.this, "200", Toast.LENGTH_SHORT).show();
                }

                if(response.code() == 401){
                    Toast.makeText(RegisterThreeActivity.this, "401", Toast.LENGTH_SHORT).show();
                }
            }

            @Override
            public void onFailure(Call<User> call, Throwable t) {

            }
        });

接口(interface):

 @FormUrlEncoded
    @POST("api/check")
    Call<User> smsPincodeCheck(@Field("email") String email,  @Field("phoneNumber") String phoneNumber);

用户模型:

public class User implements Serializable {
    private final static String TAG = "User";

    @SerializedName("user")
    @Expose
    private Long id;
    private Long commerceId;
    private String email;
    private String name;
    private String lastname;
    private String dni;
    private String companyCharge;
.
.
. Getters and setters

JSON:

这是我要发送到服务器的 json:

{
  "phoneNumber" : "444444444", 
  "email" : "example@example.com"
}

编辑 1:

Call<ResponseSMS> call = apiService.smsPincodeCheck(getPhoneNuber, email);
    call.enqueue(new Callback<ResponseSMS>() {
        @Override
        public void onResponse(Call<ResponseSMS> call, Response<ResponseSMS> response) {
            if(response.isSuccess()){
                Toast.makeText(RegisterThreeActivity.this, "200", Toast.LENGTH_SHORT).show();
            }

            if(response.code() == 401){
                Toast.makeText(RegisterThreeActivity.this, "401", Toast.LENGTH_SHORT).show();
            }
        }

        @Override
        public void onFailure(Call<ResponseSMS> call, Throwable t) {
            Toast.makeText(RegisterThreeActivity.this, "Failure", Toast.LENGTH_SHORT).show();
        }
    });
}

接口(interface):

Call<ResponseSMS> smsPincodeCheck(@Field("email") String email, @Field("phoneNumber") String phoneNumber);

型号:

public class ResponseSMS {
    public String response;
    public int status;

    public String getResponse() {
        return response;
    }

    public void setResponse(String response) {
        this.response = response;
    }

    public int getStatus() {
        return status;
    }

    public void setStatus(int status) {
        this.status = status;
    }
}

Answer 1

现在您需要制作一个单独的模型类来处理您的网络服务的响应:

public class Response {
public String response;
public int status;
}

并将此类替换为 User在您的改造网络服务调用中。

替换User与 Response在 : 1. 你的smsPincodeCheck ApiInterface的方法|界面。 2. Call<Response> call = apiService.smsPincodeCheck(getPhoneNuber, email); 3.

call.enqueue(new Callback<Response>() {
            @Override
            public void onResponse(Call<Response> call, Response<Response> response) {
                if(response.isSuccess()){
                    Toast.makeText(RegisterThreeActivity.this, "200", Toast.LENGTH_SHORT).show();
                }

                if(response.code() == 401){
                    Toast.makeText(RegisterThreeActivity.this, "401", Toast.LENGTH_SHORT).show();
                }
            }

            @Override
            public void onFailure(Call<Response> call, Throwable t) {

            }
        });