php - 如何在codeigniter中的一列中插入多个字段数据

Question

我有一个由多个复选框和输入字段组成的表单，我想将该数据插入到表的单列中，这是我的表单:

 <div id="container">
        <h1>property Detail</h1>
    <form action="" method="post">
    <table>
    <tr>
    <td> 
    Possesion
    <input type="checkbox" name="feature[]" value="possesion">
    </td>
    <td> 
    Possesion1
    <input type="checkbox" name="feature" value="possesion1">
    </td>
    <td> 
    Possesion2
    <input type="checkbox" name="feature" value="possesion2">
    </td>
    <td> 
    Possesion3
    <input type="checkbox" name="feature" value="possesion3">
    </td>
    <td> 
    Possesion4
    <input type="checkbox" name="feature" value="possesion4">
    </td>
    </td>
    </tr>

    <tr> 
    <td> <input type="submit" name="submit" value="submit"></td>
    </tr>
    </table>
    </form>

    </div>

这是我的 Controller :

 function index(){
            $this->load->view('form');

            if($_POST){


            $data_feature  = array (
           'feature' => $_POST['feature']
             );

            $data['var']= $this->Mdata->p_detail($data_feature);
            }   

        }

这是我的模型:

   function p_detail($data_feature){
             $this->db->insert('feature',$data_feature);
             return $this->db->insert_id();


}

我在表中只获取一个特征值，我想获取用户选中的复选框的所有值。

问候

Answer 1

最好的保存方法是json_encode，将数据制成json字符串。保存数据的方法有很多，如下所示:

首先更正 html，使所有同名字段都作为数组，如下所示:

<input type="checkbox" name="feature[]" value="possesion">

方法一:

将数据作为 json 字符串保存:

$this->db->insert('feature',json_encode($data));//data is an array need to insert()

方法2:

将数据作为序列化数组:

$this->db->insert('feature',serialize($data));

方法3:

将数据数组设置为字符串:

$this->db->insert('feature',implode(",",$data));

如果您想逐行插入，则在循环中迭代发布的值，如下所示:

function index(){

            $this->load->view('form');

            if($_POST){

                $data_feature  = $_POST['feature'];

                $data = [];
                foreach($data_feature as $f_key => $f_value){

                    $data[$f_key]['var']= $this->Mdata->p_detail($f_value);

                }

            }   

        }

你的模态用法为；

function p_detail($data_feature){

             $this->db->insert('feature',$data_feature);//inserts into a single column 
             return $this->db->insert_id();//returns last inserted id

}