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php - 如何在提交之前使用 jquery ajax 验证表单?

转载 作者:行者123 更新时间:2023-11-29 19:15:07 24 4
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我有这个示例代码,它使用 jquery ajax 提交表单。但问题是当我提交它时它不会存储到我的数据库中。这里似乎有什么问题?

HTML 文件

<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Signup</title>
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<!-- Latest compiled and minified CSS -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" integrity="sha384-BVYiiSIFeK1dGmJRAkycuHAHRg32OmUcww7on3RYdg4Va+PmSTsz/K68vbdEjh4u" crossorigin="anonymous">
<!-- Optional theme -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap-theme.min.css" integrity="sha384-rHyoN1iRsVXV4nD0JutlnGaslCJuC7uwjduW9SVrLvRYooPp2bWYgmgJQIXwl/Sp" crossorigin="anonymous">
</head>
<body>
<!-- Navigation Bar -->
<nav class="navbar navbar-inverse">
<div class="container-fluid">
<div class="navbar-header">
<button type="button" class="navbar-toggle" data-toggle="collapse" data-target="#myNavbar">
<span class="icon-bar"></span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
</button>
<a class="navbar-brand" href="index.html">First Day Training</a>
</div>
<div class="collapse navbar-collapse" id="myNavbar">
<ul class="nav navbar-nav navbar-right">
<li><a href="index.html"><span class="glyphicon glyphicon-step-backward"></span>Back</a></li>
</ul>
</div>
</div>
</nav>

<!-- Main Content -->
<div class="container">
<div class="row centered-form">
<div class="col-xs-12 col-sm-8 col-md-4 col-sm-offset-2 col-md-offset-4">
<div class="panel panel-default">
<div class="panel-heading">
<h3 class="panel-title">Please sign up <small>God bless!</small></h3>
</div>
<div class="panel-body">
<form role="form" method="post">
<div class="form-group">
<input type="text" name="user_name" id="username" class="form-control input-sm" placeholder="Username" autofocus >
</div>
<div class="row">
<div class="col-xs-6 col-sm-6 col-md-6">
<div class="form-group">
<input type="text" name="first_name" id="first_name" class="form-control input-sm" placeholder="First Name" >
</div>
</div>
<div class="col-xs-6 col-sm-6 col-md-6">
<div class="form-group">
<input type="text" name="last_name" id="last_name" class="form-control input-sm" placeholder="Last Name" >
</div>
</div>
</div>

<div class="form-group">
<input type="email" name="email_address" id="email" class="form-control input-sm" placeholder="Email Address" >
</div>

<div class="row">
<div class="col-xs-6 col-sm-6 col-md-6">
<div class="form-group">
<input type="password" name="password" id="password" class="form-control input-sm" placeholder="Password" >
</div>
</div>
<div class="col-xs-6 col-sm-6 col-md-6">
<div class="form-group">
<input type="password" name="password_confirmation" id="password_confirmation" class="form-control input-sm" placeholder="Confirm Password" onChange="checkPasswordMatch();" >
</div>
</div>
</div>
<div>
<div id="divCheckPasswordMatch"></div>
</div>
<input type="submit" id="submit" value="Register" class="btn btn-info btn-block">
</form>
</div>
</div>
</div>
</div>
</div>
</body>
<!-- Password Validation -->
<script>
function checkPasswordMatch() {
var password = $("#password").val();
var confirmPassword = $("#password_confirmation").val();

if (password != confirmPassword)
$("#divCheckPasswordMatch").html("Passwords do not match!");
else
$("#divCheckPasswordMatch").html("Passwords match.");
}

$(document).ready(function () {
$("#password_confirmation").keydown(checkPasswordMatch);
});
</script>

<script>
$(document).ready(function(){
$("#submit").click(function(){
var username = $("#username").val();
var firstname = $("#first_name").val();
var lastname = $("#last_name").val();
var email = $("#email").val();
var password = $("#password").val();
var checkpassword = $("#password_confirmation").val();
// Returns successful data submission message when the entered information is stored in database.
var dataString = 'user_name='+ username + '&first_name='+ firstname + '&last_name='+ lastname + '&email_address='+ email + '&password='+ password;
if(username==''|| firstname=='' || lastname=='' || email==''||password=='')
{
alert("Please Fill All Fields");
}
else if(!filter_var(email, FILTER_VALIDATE_EMAIL))
{
alert("Invalid email format");
}
else if(password != checkpassword)
{
alert("Password does not match.");
}
else
{
// AJAX Code To Submit Form.
$.ajax({
type: "POST",
url: "signupbackend.php",
data: dataString,
cache: false,
success: function(result){
alert(result);
}
});
}
return false;
});
});
</script>

<!-- Latest compiled and minified JavaScript -->
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js" integrity="sha384-Tc5IQib027qvyjSMfHjOMaLkfuWVxZxUPnCJA7l2mCWNIpG9mGCD8wGNIcPD7Txa" crossorigin="anonymous"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
</html>

PHP 代码

<?php
//include external connection.php
include "connection.php";

// prepare an sql statement
$stmt = $conn->prepare("INSERT INTO users (username, password, firstname, lastname, email) VALUES (?, ?, ?, ?, ?)");
//bind the sql statement
$stmt->bind_param("sssss", $username, $password, $firstname, $lastname, $email);

// set parameters and execute
$username = mysql_escape_string($_POST["user_name"]);
$password = mysql_escape_string($_POST["password"]);
$checkpassword = mysql_escape_string($_POST["password_confirmation"]);
$firstname = mysql_escape_string($_POST["first_name"]);
$lastname = mysql_escape_string($_POST["last_name"]);
$email = mysql_escape_string($_POST["email_address"]);

$stmt->execute(); //execute the statement

//display alert message
echo "<script>alert('New record created.');</script>";
$stmt->close(); //close the statement
$conn->close(); //close the connection
?>

这是将在不刷新页面的情况下提交表单的代码。但它似乎没有将数据存储在数据库中。请帮忙。

JQuery 提交

 <script>
$(document).ready(function(){
$("#submit").click(function(){
var username = $("#username").val();
var firstname = $("#first_name").val();
var lastname = $("#last_name").val();
var email = $("#email").val();
var password = $("#password").val();
var checkpassword = $("#password_confirmation").val();
// Returns successful data submission message when the entered information is stored in database.
var dataString = 'user_name='+ username + '&first_name='+ firstname + '&last_name='+ lastname + '&email_address='+ email + '&password='+ password;
if(username==''|| firstname=='' || lastname=='' || email==''||password=='')
{
alert("Please Fill All Fields");
}
else if(!filter_var(email, FILTER_VALIDATE_EMAIL))
{
alert("Invalid email format");
}
else if(password != checkpassword)
{
alert("Password does not match.");
}
else
{
// AJAX Code To Submit Form.
$.ajax({
type: "POST",
url: "Model/signupbackend.php",
data: dataString,
cache: false,
success: function(result){
alert(result);
}
});
}
return false;
});
});
</script>

最佳答案

  • jquery-validate是一个很好的jquery验证插件。你可以试试。

  • 要定位 bug,您可以在 php 代码中添加 echovar_dump 来检查后端是否收到了正确的参数。然后尝试检查开发工具发送的请求jquery(可以在chrome中按F12)

关于php - 如何在提交之前使用 jquery ajax 验证表单?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42777958/

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