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php - Codeigniter 获取数据时出错

转载 作者:行者123 更新时间:2023-11-29 19:11:27 25 4
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我用 php 编写了一个程序,它工作正常(php 程序工作正常,而不是 codeigniter 版本)。现在,我想使用 Codeigniter 制作该程序。

这是我的 php 程序:

    <?php include('connect.php');

?>

<html>
<head>

<script src="http://code.jquery.com/jquery-2.1.1.min.js"></script>
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" integrity="sha384-BVYiiSIFeK1dGmJRAkycuHAHRg32OmUcww7on3RYdg4Va+PmSTsz/K68vbdEjh4u" crossorigin="anonymous">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap-theme.min.css" integrity="sha384-rHyoN1iRsVXV4nD0JutlnGaslCJuC7uwjduW9SVrLvRYooPp2bWYgmgJQIXwl/Sp" crossorigin="anonymous">
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js" integrity="sha384-Tc5IQib027qvyjSMfHjOMaLkfuWVxZxUPnCJA7l2mCWNIpG9mGCD8wGNIcPD7Txa" crossorigin="anonymous"></script>

</head>
<body>

<div class="container">
<div class="row">
<div class="col-md-12">



<a href="estudiante.php"><button type="button" class="btn btn-success">AGREGAR</button></a><br /><br />
<h2 align="center">TABLA:MATERIAS</h2>
<input id="busqueda_tabla" type="text">
<table class="table table-hover" align="center" border="1" cellspacing="0" cellpadding="0" width="700" id="tabla_busqueda">
<thead>
<th>id</th>
<th>Carrera</th>
<th>Nombre</th>
<th>Descripcion</th>
<th>Carga horaria (hs)</th>
<th>Accion</th>
</thead>

<?php

$sql=mysql_query("SELECT s.*, c.nombre AS carrera FROM materias s LEFT JOIN carreras c ON s.carrera_id=c.id");//ESTA FUNCION ME AYUDA A ACOMODAR LAS CARRERAS EN LA COLUMNA "CARRERA" DE LA TABLA
$i=1;
while($row=mysql_fetch_array($sql)){
echo "<tr>
<td>".$i."</td>
<td>".$row['carrera']."</td>
<td>".$row['nombre']."</td>
<td>".$row['descripcion']."</td>
<td>".$row['carga_horaria']."</td>
<td align='center'>
<a href='editar.php?editar=1&iden=".$row['id']."'><button type='button' class='btn btn-primary'>EDITAR</button></a> |
<a href='borrar.php?borrar=1&iden=".$row['id']."'><button type='button' class='btn btn-danger'>BORRAR</button></a>
</td>
</tr>";
$i++;

}
?>


</table>

</div>
</div>
</div>

</body>



</html>

还有“connect.php”文件

    <?php

$con=mysql_connect('localhost','root','root')OR die('error : '.mysql_error());
$db=mysql_select_db('desafio');

if($db){
echo '';

}else{
echo 'Error :' .mysql_error();
}


?>

这是我的 Codeigniter 代码:

我的“查看”文件:

<?php include('header.php'); ?>

<?php include('footer.php'); ?>


<div class="container">
<div class="row">
<div class="col-md-12">

<h2 align="center">TABLA:MATERIAS</h2>
<input id="busqueda_tabla" type="text">
<table class="table table-hover" align="center" border="1" cellspacing="0" cellpadding="0" width="700" id="tabla_busqueda">
<thead>
<th>id</th>
<th>Carrera</th>
<th>Nombre</th>
<th>Descripcion</th>
<th>Carga horaria (hs)</th>
<th>Accion</th>
</thead>


<?php
$i=1;
foreach($records as $record) {

echo "<tr>
<td>".$i."</td>
<td>".$record->carrera."</td>
<td>".$record->nombre."</td>
<td>".$record->descripcion."</td>
<td>".$record->carga_horaria."</td>
<td align='center'>
<a href='editar.php?editar=1&iden=".$record->id."'><button type='button' class='btn btn-primary'>EDITAR</button></a> |
<a href='borrar.php?borrar=1&iden=".$record->id."'><button type='button' class='btn btn-danger'>BORRAR</button></a>
</td>
</tr>";
}
$i++;
?>
</table>

</div>
</div>
</div>

这是我的 Crudmodel 文件:

      <?php

Class Crudmodel extends CI_Model{

public function getRecords(){

$this->db->select('s.*, c.nombre AS carrera')
->from('materias s')
->join('carreras c', 's.carrera_id = c.id', 'left');
$q = $this->db->get();

if($q -> num_rows() > 0){

return $q->result();
}

return false;

}

}


?>

和 Controller 文件:

    <?php

class Home extends CI_Controller{

public function index(){
$this->load->model('Crudmodel');
$data['records'] = $this->Crudmodel->getRecords();
$this->load->view('home', $data['records']);

}
}
?>

但它不起作用,我收到此错误:

https://i.gyazo.com/607303edcd861d0a2257611c925f3e6e.png
https://i.gyazo.com/eb9d833bf5d0818db2906ec1447550c0.png
https://i.gyazo.com/c5bb77d50315888a375a1e775a5ad68c.png

我的数据库和自动加载文件:

https://i.gyazo.com/ef7eb80b6f484e4831b78a3408a05b48.png
https://i.gyazo.com/ecf3de9845ed039f877613ffef4e6aa7.png

不知道该怎么办:/,可以帮我解决吗?

最佳答案

使用它

$sql=mysql_query("SELECT s.*, c.nombre AS carrera FROM materias s LEFT JOIN carreras c ON s.carrera_id=c.carrera_id"); 

而不是

$sql=mysql_query("SELECT s.*, c.nombre AS carrera FROM materias s LEFT JOIN carreras c ON s.carrera_id=c.id");

关于php - Codeigniter 获取数据时出错,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43047837/

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