gpt4 book ai didi

php - 尝试显示可使用 ajax 和 php 编辑的实时表

转载 作者:行者123 更新时间:2023-11-29 19:10:09 25 4
gpt4 key购买 nike

我有四个不同的文件

index.php
select.php
insert.php
edit.php
delete.php

在我的后端,我创建了一个名为“ecc”的数据库

数据库“ecc”具有名为“task”的表

表任务具有以下字段

ID、名称、类别、费用

id 的数据类型设置为 int 且索引为主,id 字段也自动递增

我的问题:我的代码仅显示“实时表数据”。

如果有人重写它或提出一些更改,那就太好了。

index.php

<html>  
<head>
<title>Live Table Data Edit</title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.0/jquery.min.js"></script>
</head>
<body>
<div class="container">
<br />
<br />
<br />
<div class="table-responsive">
<h3 align="center">Live Table Add Edit Delete using Ajax Jquery in PHP Mysql</h3><br />
<div id="live_data"></div>
</div>
</div>
</body>
</html>
<script>

$(document).ready(function(){
function fetch_data()
{
$.ajax({
url:"select.php",
method:"POST",
success:function(data){
$('#live_data').html(data);
}
});
}

fetch_data();
$(document).on('click', '#btn_add', function(){

var name = $('#name').text();
var category = $('#category').text();
var cost = $('#cost').text();

if(name == '')
{
alert("Enter Service Name");
return false;
}

if(category == '')
{
alert("Enter Category of Service");
return false;
}

if(cost == '')
{
alert("Enter cost");
return false;
}
$.ajax({
url:"insert.php",
method:"POST",
data:{name:name, category:category, cost:cost},
dataType:"text",
success:function(data)
{
alert(data);
fetch_data();
}
})
});
function edit_data(id, text, column_name)
{
$.ajax({
url:"edit.php",
method:"POST",
data:{id:id, text:text, column_name:column_name},
dataType:"text",
success:function(data){
alert(data);
}
});
}
$(document).on('blur', '.name', function(){
var id = $(this).data("id1");
var name = $(this).text();
edit_data(id, name, "name");
});
$(document).on('blur', '.category', function(){
var id = $(this).data("id2");
var category = $(this).text();
edit_data(id,category, "category");

$(document).on('blur', '.cost', function(){
var id = $(this).data("id3");
var category = $(this).text();
edit_data(id,cost, "cost");
});

$(document).on('click', '.btn_delete', function(){
var id=$(this).data("id4");
if(confirm("Are you sure you want to delete this?"))
{
$.ajax({
url:"delete.php",
method:"POST",
data:{id:id},
dataType:"text",
success:function(data){
alert(data);
fetch_data();
}
});
}
});
});
</script>

select.php

<?php  
$connect = mysqli_connect("localhost", "root", "", "ecc");
$output = '';
$sql = "SELECT * FROM task ORDER BY id DESC";
$result = mysqli_query($connect, $sql);
$output .= '
<div class="table-responsive">
<table class="table table-bordered">
<tr>
<th width="10%">Id</th>
<th width="40%">First Name</th>
<th width="40%">Last Name</th>
<th width="10%">Delete</th>
</tr>';
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td>'.$row["id"].'</td>
<td class="name" data-id1="'.$row["id"].'" contenteditable>'.$row["name"].'</td>
<td class="category" data-id2="'.$row["id"].'" contenteditable>'.$row["category"].'</td>
<td class="cost" data-id3="'.$row["id"].'" contenteditable>'.$row["cost"].'</td>
<td><button type="button" name="delete_btn" data-id4="'.$row["id"].'" class="btn btn-xs btn-danger btn_delete">x</button></td>
</tr>
';
}
$output .= '
<tr>
<td></td>
<td id="name" contenteditable></td>
<td id="category" contenteditable></td>
<td id="cost" contenteditable></td>
<td><button type="button" name="btn_add" id="btn_add" class="btn btn-xs btn-success">+</button></td>
</tr>
';
}
else
{
$output .= '<tr>
<td colspan="4">Data not Found</td>
</tr>';
}
$output .= '</table>
</div>';
echo $output;
?>

插入.php

<?php  
$connect = mysqli_connect("localhost", "root", "", "test_db");
$sql = "INSERT INTO tbl_sample(name, category, cost) VALUES('".$_POST["name"]."', '".$_POST["category"]."', '".$_POST["cost"]."')";
if(mysqli_query($connect, $sql))
{
echo 'Data Inserted';
}
?>

edit.php

<?php  
$connect = mysqli_connect("localhost", "root", "", "ecc");
$id = $_POST["id"];
$text = $_POST["text"];
$column_name = $_POST["column_name"];
$sql = "UPDATE task SET ".$column_name."='".$text."' WHERE id='".$id."'";
if(mysqli_query($connect, $sql))
{
echo 'Data Updated';
}
?>

删除.php

<?php  
$connect = mysqli_connect("localhost", "root", "", "ecc");
$sql = "DELETE FROM task WHERE id = '".$_POST["id"]."'";
if(mysqli_query($connect, $sql))
{
echo 'Data Deleted';
}
?>

最佳答案

您可以使用数据表来实现此目的,不需要所有这些

https://editor.datatables.net/examples/inline-editing/simple

检查一下,数据表为此提供了库

关于php - 尝试显示可使用 ajax 和 php 编辑的实时表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43154426/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com