Android:如何检查两个单击按钮中的两个数字是否相等(内存游戏)？

Question

有人可以告诉我如何检查两个数字是否相等吗？我正在制作内存游戏进行练习。用户单击一个显示一个数字的按钮，然后单击另一个显示第二个数字的按钮。如何检查这两个数字是否相同，因为如果它们相同，则需要保持可见，如果它们不相同，则需要再次隐藏。

我的适配器:

package com.example.korisnik.assignment;

import android.content.Context;
import android.view.View;
import android.view.ViewGroup;
import android.widget.BaseAdapter;
import android.widget.Button;
import android.widget.GridView;
import java.util.ArrayList;
import java.util.Collections;

public class ButtonAdapter extends BaseAdapter {

Button[] buttons;
public Context c;

public ButtonAdapter(Context c) {
    final ArrayList<Integer> numbers = new ArrayList<Integer>();
    for (int i=1; i<=5; i++) {
        numbers.add(i);
    }
    for (int i=1; i<=4; i++) {
        numbers.add(i);
    }
    Collections.shuffle(numbers);
    this.c = c;
    buttons = new Button[9];
    for(int i=0;i<buttons.length;i++) {
        final int o = i;
        buttons[i] = new Button(c);
        buttons[i].setBackgroundResource(R.mipmap.block);
        buttons[i].setLayoutParams(new GridView.LayoutParams(300,300));
        buttons[i].setTag(0);
        buttons[i].setTextSize(20);
        buttons[i].setText("X");
        buttons[i].setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                Button btn = (Button) v;
                btn.setText(String.valueOf(numbers.get(o)));
            }
        });
    }
}

@Override
public int getCount() {
    return buttons.length;
}

@Override
public Object getItem(int i) {
    return buttons[i];
}

@Override
public long getItemId(int i) {
    return 0;
}

@Override
public View getView(int i, View view, ViewGroup viewGroup) {
    return buttons[i];
}
}

Answer 1

试试这段代码。

public class ButtonAdapter extends BaseAdapter {

Button[] buttons;
public Context c;
//Store previous clicked number
private String mPreviousvValue;

public ButtonAdapter(final Context c) {
    final ArrayList<Integer> numbers = new ArrayList<Integer>();
    for (int i = 1; i <= 5; i++) {
        numbers.add(i);
    }
    for (int i = 1; i <= 4; i++) {
        numbers.add(i);
    }
    Collections.shuffle(numbers);
    this.c = c;
    buttons = new Button[9];
    for (int i = 0; i < buttons.length; i++) {
        final int o = i;
        buttons[i] = new Button(c);
        buttons[i].setBackgroundResource(R.mipmap.block);
        buttons[i].setLayoutParams(new GridView.LayoutParams(300, 300));
        buttons[i].setTag(0);
        buttons[i].setTextSize(20);
        buttons[i].setText("X");
        buttons[i].setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                String currentValue = String.valueOf(numbers.get(o));
                Button btn = (Button) v;
                if(mPreviousvValue!=null){
                 if (mPreviousvValue.equalsIgnoreCase(currentValue)) {
                    // Show Numbers equal
                  } else {
                    // Show Numbers not equal
                  }
                }
                btn.setText(currentValue);
                mPreviousvValue = currentValue;
            }
        });
    }
}

@Override
public int getCount() {
    return buttons.length;
}

@Override
public Object getItem(int i) {
    return buttons[i];
}

@Override
public long getItemId(int i) {
    return 0;
}

@Override
public View getView(int i, View view, ViewGroup viewGroup) {
    return buttons[i];
}
}

编辑 1:说明

将其添加为全局变量以存储之前单击的值

private String mPreviousvValue; 

然后在 onclick 中检查点击按钮的当前值是否等于之前的值。

 @Override
  public void onClick(View v) {
      String currentValue = String.valueOf(numbers.get(o));
      Button btn = (Button) v;
      if(mPreviousvValue!=null){
       if (mPreviousvValue.equalsIgnoreCase(currentValue)) {
          // Show Numbers equal
        } else {
          // Show Numbers not equal
         }
       }
       btn.setText(currentValue);
       mPreviousvValue = currentValue;
  }

编辑 2:正如您要求在按钮值不同时清除旧 View

添加一个公共(public)变量来存储以前的按钮位置

private int mPreviousPos=-1; 

然后在 onclick 中存储第一次单击的按钮位置，当用户第二次单击时，如果值不相等，则从数组中获取按钮引用并清除两者，如代码所示。

 @Override
                public void onClick(View v) {
                    String currentValue = String.valueOf(numbers.get(o));
                    Button btn = (Button) v;
                    if(mPreviousvValue!=null && mPreviousPos!=-1){
                        if (mPreviousvValue.equalsIgnoreCase(currentValue)) {

                            // Show Numbers equal
                        } else {
                            // Show Numbers not equal
                            //Clear previous button
                            Button button=buttons[mPreviousPos];
                            button.setText("X");

                        }
                    }
                    btn.setText(currentValue);
                    mPreviousvValue = currentValue;
                    mPreviousPos=o;
                }