gpt4 book ai didi

c# - 从公钥字节数组重新创建椭圆曲线的 X 和 Y

转载 作者:行者123 更新时间:2023-11-29 19:01:30 26 4
gpt4 key购买 nike

我对密码学真的很陌生,但是 - 我想做的是从公钥的字节数组表示中获取 X 和 Y 坐标。我正在使用 secp256r1 曲线。

// get curve
X9ECParameters x9 = ECNamedCurveTable.GetByName("secp256r1");
ECCurve curve = x9.Curve;

// get coordinates from ASN.1 encoded public key point
var asn1 = (Asn1Sequence)Asn1Object.FromByteArray(publicKeyBytes);
var at1 = (DerBitString)asn1[1];
var bytes = at1.GetBytes();
var x = bytes.Skip(1).Take(32).Reverse().ToArray();
var y = bytes.Skip(33).Take(32).Reverse().ToArray();

// get affine X and Y using point on curve from X and Y
var ecPoint = curve.CreatePoint(new Org.BouncyCastle.Math.BigInteger(1, x), new Org.BouncyCastle.Math.BigInteger(1, y));
ECDomainParameters dParams = new ECDomainParameters(curve, ecPoint, x9.N);
ECPublicKeyParameters pubKey = new ECPublicKeyParameters(ecPoint, dParams);
var affineX = pubKey.Q.AffineXCoord.ToBigInteger().ToByteArrayUnsigned();
var affineY = pubKey.Q.AffineYCoord.ToBigInteger().ToByteArrayUnsigned();

// return a tuple of the coordinates
return (affineX, affineY);

我收到 X 和 Y 坐标,但这些可能不正确。我究竟做错了什么?谢谢

最佳答案

好的,所以,代码几乎没有问题。这是有效的版本,也许它会对某人有所帮助

internal static (string x, string y) GetCertificateCoordinates(byte[] publicKeyBytes)
{
// parse based on asn1 format the content of the certificate
var asn1 = (Asn1Sequence)Asn1Object.FromByteArray(publicKeyBytes);
var at1 = (DerBitString)asn1[1];
var xyBytes = at1.GetBytes();

//retrieve preddefined parameters for P256 curve
X9ECParameters x9 = ECNamedCurveTable.GetByName("P-256");
//establish domain we will be looking for the x and y
ECDomainParameters domainParams = new ECDomainParameters(x9.Curve, x9.G, x9.N, x9.H, x9.GetSeed());
ECPublicKeyParameters publicKeyParams = new ECPublicKeyParameters(x9.Curve.DecodePoint(xyBytes), domainParams);
//get the affine x and y coordinates
var affineX = EncodeCordinate(publicKeyParams.Q.AffineXCoord.ToBigInteger());
var affineY = EncodeCordinate(publicKeyParams.Q.AffineYCoord.ToBigInteger());

return (affineX, affineY);
}

public static string EncodeCordinate(Org.BouncyCastle.Math.BigInteger integer)
{
var notPadded = integer.ToByteArray();
int bytesToOutput = (256 + 7) / 8;
if (notPadded.Length >= bytesToOutput)
return Jose.Base64Url.Encode(notPadded);
var padded = new byte[bytesToOutput];
Array.Copy(notPadded, 0, padded, bytesToOutput - notPadded.Length, notPadded.Length);
return Jose.Base64Url.Encode(padded);
}

我在 android 中使用此代码作为 JWT 在 header 中将 X 和 Y 作为 jwk 提供给服务器端

关于c# - 从公钥字节数组重新创建椭圆曲线的 X 和 Y,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48929222/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com