javascript - 组合数组并插入差异

Question

假设我有两个对象，object_one

{
  1: {item1 /*updated*/}, //note updated represents more recent item1 data
  2: {item1 /*updated*/},
  3: {item1 /*updated*/}
}

和object_two

{
  1: {item1, item2, item3},
  2: {item1, item2, item3},
  4: {item1, item2, item3},
  5: {item1, item2, item3}
}

我想将 object_one 添加到 object_two 中，添加 object_two 没有的任何元素。我还想获取 object_two 的 item1 版本并将它们更新为 object_one 的值

想要的结果

{
  1: {item1 /*updated*/, item2, item3},
  2: {item1 /*updated*/, item2, item3},
  3: {item1 /*updated*/},
  4: {item1, item2, item3},
  5: {item1, item2, item3}
}

我自己尝试过，但我的解决方案是手动的，不适用于 object_one 和 object_two 的所有长度。一些方向将不胜感激

Answer 1

参见 Object.entries和 Object.assign了解更多信息。

// Original.
const original = {
  1: {A: '1A', B: '1B', C: '1C'},
  2: {A: '2A', B: '2B', C: '2C'},
  4: {A: '4A', B: '4B', C: '4C'},
  5: {A: '5A', B: '5B', C: '5C'}
}

// Merge.
const update = {
  1: {A: '1A updated'},
  2: {B: '2B updated'},
  3: {C: '3C updated'}
}

// Combine.
const merge = (original, update) => {
  const x = {...original}
  Object.entries(update).forEach(([key, value]) => {
    x[key] = Object.assign({}, x[key], value)
  })
  return x
}

// Output.
const output = merge(original, update)

// Proof.
console.log(output)