mysql - 创建 Hibernate 来连接表

Question

我必须加入 2 张 table 。想要加入的列是来自候选表的电子邮件和来自用户表的密码。怎么做。有人能帮我吗。候选人表格如下:

CREATE TABLE `candidate` (`candidate_id` bigint(12) NOT NULL,`user_id`int(11) DEFAULT NULL,`firstname` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`lastname` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`dob` date DEFAULT NULL,`gender` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`email` varchar(100) COLLATE utf8_unicode_ci NOT NULL,`phone` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL, `address_id` int(11) DEFAULT NULL, `profile_title` varchar(120) COLLATE utf8_unicode_ci DEFAULT NULL, `profile_summary` varchar(10000) COLLATE utf8_unicode_ci DEFAULT NULL, `total_experience` int(11) DEFAULT NULL COMMENT 'year,month', `current_location` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL, `current_salary` double DEFAULT NULL, `expected_salary` double DEFAULT NULL, `status` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL, `percentage` int(45) DEFAULT NULL,`updated_on` timestamp NULL DEFAULT CURRENT_TIMESTAMP, `noticeperiod` int(11) DEFAULT NULL, `martialstatus` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL, `currentoffer` double DEFAULT NULL, `idproof` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL, `industry` varchar(200) COLLATE utf8_unicode_ci DEFAULT NULL,`functionalarea` varchar(200) COLLATE utf8_unicode_ci DEFAULT NULL, `functionalrole` varchar(200) COLLATE utf8_unicode_ci DEFAULT NULL, `resign` bit(1) DEFAULT NULL,`preferlocation` varchar(1000) COLLATE utf8_unicode_ci DEFAULT NULL,`type` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`notice_period_update` timestamp NULL DEFAULT NULL `passport` bit(1) DEFAULT NULL,`gross_salary` double DEFAULT NULL,`profile_type` varchar(12) COLLATE utf8_unicode_ci DEFAULT NULL,`rrm_user_id` int(11) DEFAULT NULL, PRIMARY KEY (`candidate_id`), KEY `Candidate_Address_idx` (`address_id`),KEY `Can_user` (`user_id`),KEY `CandidateStatus_idx` (`status`),KEY `CandidatePercent_idx` (`percentage`),KEY `user_id_idx` (`rrm_user_id`),CONSTRAINT `Can_user` FOREIGN KEY (`user_id`) REFERENCES `user` (`id`) ON DELETE CASCADE ON UPDATE CASCADE,CONSTRAINT `Candidate_Address`FOREIGN KEY (`address_id`) REFERENCES `address` (`id`) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `user_id` FOREIGN KEY (`rrm_user_id`) REFERENCES `user` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;

用户是:

CREATE TABLE `user` (`id` int(11) NOT NULL AUTO_INCREMENT,`username` varchar(255) COLLATE utf8_unicode_ci NOT NULL,`password` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`first_name` varchar(100) COLLATE utf8_unicode_ci DEFAULT NULL, `last_name` varchar(100) COLLATE utf8_unicode_ci DEFAULT NULL,`type` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`active` bit(1) DEFAULT NULL,`deleted` bit(1) DEFAULT NULL,`timezone` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`created_on` timestamp NULL DEFAULT NULL,`updated_on` timestamp NULL DEFAULT CURRENT_TIMESTAMP,`activationcode` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`secure_key` varchar(16) COLLATE utf8_unicode_ci DEFAULT NULL,PRIMARY KEY (`id`),UNIQUE KEY `username_UNIQUE` (`username`)) ENGINE=InnoDB AUTO_INCREMENT=1505 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;

Answer 1

您需要一个非常简单的 SQL 查询来执行此操作:

SELECT
  c.candidate_id,
  c.user_id,
  c.email,
  u.password
FROM
  candidate as c
JOIN user as u ON c.user_id = u.user_id

工作示例: http://sqlfiddle.com/#!9/0ba876/1

在尝试在该领域取得进展之前，请先尝试学习一些 SQL。 https://www.w3schools.com/sql/