mysql - 在 ireport 中使用 SQL 查询来报告用户反馈

Question

我的查询遇到问题。我实际上有一个具有以下设置的数据库: 奥 git _a我用它从反馈机器插入我的数据。提供的数据就像这个例子:
R;标识符
P34567；研究编号
2015 年 5 月 5 日；研究日期
10:32:39；研究时间
02;问题编号(2-5)
04;用户评价(1-5)。
第333章 合作者ID


我需要为每个合作者构建一份报告，以及一份显示某个部门的所有合作者的综合报告。该扇区的内容尚未实现，因此我正在考虑来自单个扇区的所有数据。

我构建了一个可以在数据库中使用几行的查询，但是当它在完整的数据库中执行时，它会卡住。

要检索我正在使用的每个协作者的数据:

select p.pergunta as Pergunta,
(select count(*) from pesquisa where pergunta=p.pergunta and colaborador= 
$P{colaborador} and resposta=1) as '1 - Excelente',
(select count(*) from pesquisa where pergunta=p.pergunta and colaborador= 
$P{colaborador} and resposta=2) as '2 - Muito Bom',
(select count(*) from pesquisa where pergunta=p.pergunta and colaborador= 
$P{colaborador} and resposta=3) as '3 - Bom',
(select count(*) from pesquisa where pergunta=p.pergunta and colaborador= 
$P{colaborador} and resposta=4) as '4 - Regular',
(select count(*) from pesquisa where pergunta=p.pergunta and colaborador= 
$P{colaborador} and resposta=5) as '5 - Ruim',
(select count(*) from pesquisa where pergunta=p.pergunta and colaborador= 
$P{colaborador} and (resposta=1 or resposta=2 or resposta=3 or resposta=4 
or resposta=5)) as 'TOTAL'
from pesquisa as p where colaborador=$P{colaborador} and data between 
$P{data_inicial} and $P{data_final}
group by pergunta;

使用此代码我可以创建此报告:DB SETUP

对于一般报告，我使用此查询:

select p.colaborador, p.pergunta as Pergunta,
(select count(*) from pesquisa where pergunta=p.pergunta and resposta=1)         
as '1 - Excelente',
(select count(*) from pesquisa where pergunta=p.pergunta and resposta=2) 
 as '2 - Muito Bom',
 (select count(*) from pesquisa where pergunta=p.pergunta and resposta=3) 
 as '3 - Bom',
 (select count(*) from pesquisa where pergunta=p.pergunta and resposta=4) 
 as '4 - Regular',
 (select count(*) from pesquisa where pergunta=p.pergunta and resposta=5) 
 as '5 - Ruim',
 (select count(*) from pesquisa where pergunta=p.pergunta and colaborador 
 = p.colaborador and (resposta=1 or resposta=2 or resposta=3 or 
 resposta=4 or resposta=5)) as 'TOTAL'
 from pesquisa as p
 group by colaborador, pergunta;

报告已生成，结果如下:无法发布更多图像

正如我所说，用几行代码它就可以完美地工作，但是当数据量很大时它就会卡住，而且我不知道如何通过另一个查询获得这个结果。我使用所有这些选择的原因是通过行计算每个问题的答案。

你们能给我一盏灯吗？

Answer 1

我的 friend 向我展示了另一种实现此结果的方法。基本上它再次子选择数据结束过滤器以显示它。

SELECT colaborador, 
   pergunta,
   SUM(EXCELENTE) AS '1 - EXCELENTE',
   SUM(MUITOBOM) AS '2 - MUITO BOM',
   SUM(BOM) AS '3 - BOM',
   SUM(REGULAR) AS '4 - REGULAR',
   SUM(RUIM) AS '5 - RUIM'
FROM (
  SELECT colaborador, 
         pergunta,
         CASE WHEN resposta = 1 THEN 1 ELSE 0 END AS 'EXCELENTE',
         CASE WHEN resposta = 2 THEN 1 ELSE 0 END AS 'MUITOBOM',
         CASE WHEN resposta = 3 THEN 1 ELSE 0 END AS 'BOM',
         CASE WHEN resposta = 4 THEN 1 ELSE 0 END AS 'REGULAR',
         CASE WHEN resposta = 5 THEN 1 ELSE 0 END AS 'RUIM'
  FROM pesquisa
  WHERE data between str_to_date($P{data_inicial}, "%d/%m/%Y") and str_to_date($P{data_final}, "%d/%m/%Y")
        and colaborador = $P{colaborador}
) AS A
GROUP BY colaborador, pergunta

它更好更快。