javascript - 如何启用和禁用 javascript 功能？

Question

             if(tmpStr == tmp+value)
             {
                i=1;
                action = null;
                action2 = null;
             }
             if(tmpStr1 == tmp+value)
             {
                i=0;
                            action();//not working
                            action2();//not working
             }
             for(i;i<=14; i++)
             {
                 if(tmp!="movie"+i) 
                 {
                    document.getElementById("movie"+i).sndToAS("resume");
                 }
             }

         }
         function action()
         {
            document.getElementById("movie0").sndToAS("pause");
         }
         function action2()
         {
            if(tmp != "movie0")
            {
                document.getElementById("movie0").sndToAS("pause");

            }
         }

Answer 1

做这样的事情

function actionFunc(){
    document.getElementById("movie0").sndToAS("pause");
}
function action2Func()
{
    if(tmp != "movie0"){
     document.getElementById("movie0").sndToAS("pause");

    }
}

window.action = actionFunc;
window.action2 = action2Func;

if(tmpStr == tmp+value)
{
    id=1;
    window.action = null;
    window.action2 = null;
}
if(tmpStr1 == tmp+value)
{
    id=0;
    window.action = actionFunc;
    window.action2 = action2Func;
}

然后当你想调用你的函数时，你所要做的就是

action();
action2();

但是你会想在调用它们之前检查它们是否已设置

我相信这就是你的追求

或者做这样的事情

function action(){
    if (window.actionEnabled)
    {
       document.getElementById("movie0").sndToAS("pause");
    }
}
function action2()
{
    if (window.action2Enabled)
    {
       if(tmp != "movie0"){
         document.getElementById("movie0").sndToAS("pause");
       }
    }
}

window.actionEnabled = true;
window.action2Enabled = true;

if(tmpStr == tmp+value)
{
    id=1;
    window.actionEnabled = false;
    window.action2Enabled = false;
}
if(tmpStr1 == tmp+value)
{
    id=0;
    window.actionEnabled = true;
    window.action2Enabled = true;
}

然后您不必检查是否已启用只需调用它们，它们将工作或需要取决于它们是否已启用