Android 创建具有 3 个圆角和 1 个直角的 ImageView

Question

我想创建一个有 3 个圆角和一个直角的 ImageView 。

设置背景可绘制不起作用，我确实找到了一些 java 代码，但它只圆了 2 个角或 4 个而不是 3 个

Bitmap output = Bitmap.createBitmap(bitmap.getWidth(), bitmap
.getHeight(), Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(output);

final int color = 0xff424242;
final Paint paint = new Paint();
final Rect rect = new Rect(0, 0, bitmap.getWidth(), 
bitmap.getHeight());
final RectF rectF = new RectF(rect);
final float roundPx = pixels;

paint.setAntiAlias(true);
canvas.drawARGB(0, 0, 0, 0);
paint.setColor(color);
canvas.drawRoundRect(rectF, roundPx, roundPx, paint);

paint.setXfermode(new 
PorterDuffXfermode(PorterDuff.Mode.SRC_IN));
canvas.drawBitmap(bitmap, rect, rect, paint);

return output;

Answer 1

那里有写得很好的库，这样你就可以将图像剪切到你想要的任何路径，但这里是代码:

private Bitmap clip(Bitmap bitmap) {
    Bitmap output = Bitmap.createBitmap(bitmap.getWidth(), bitmap
            .getHeight(), Bitmap.Config.ARGB_8888);
    Canvas canvas = new Canvas(output);

    final Paint paint = new Paint();
    paint.setAntiAlias(true);


    // creating a closing path with 3 rounded corners
    Path path = new Path();
    float radius = 48;
    float diameter = radius * 2;
    float width = bitmap.getWidth();
    float height = bitmap.getHeight();
    path.addArc(0, 0, diameter, diameter, 180, 90);
    path.lineTo(width - radius, 0);
    path.arcTo(width - diameter, 0, width, diameter, 270, 90, false);
    path.lineTo(width, height);
    path.lineTo(radius, height);
    path.arcTo(0, height - diameter, diameter, height, 90, 90, false);
    path.close();


    paint.setShader(new BitmapShader(bitmap, Shader.TileMode.CLAMP, Shader.TileMode.CLAMP));
    canvas.drawPath(path, paint);

    return output;

}