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php - INSERT INTO 2表查询

转载 作者:行者123 更新时间:2023-11-29 18:07:29 26 4
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我正在尝试将一个查询插入到 2 个表中,但不起作用。我想将所有 _POST 数据保存到“tours”表和图像库介绍“poze_articol”表中,其中 poze_articol 中的“pid”是 tours id 的 id,一些帮助感谢您,因为我是 php 新手,谢谢!

PHP 代码:

<?php
$dbhost = '';
$dbuser = '';
$dbpass = '';
$myDBname = '';
$conn = mysql_connect($dbhost, $dbuser, $dbpass, $myDBname);
$db_selected = mysql_select_db('antonytravel', $conn);
if (!$db_selected) {
die ('Can\'t use antonytravel : ' . mysql_error());
}
if(isset($_POST['addtour']))
{
if (!isset($_FILES['poza_caseta']['tmp_name'])) {
echo "";
}else{
$file=$_FILES['poza_caseta']['tmp_name'];
$image= addslashes(file_get_contents($_FILES['poza_caseta']['tmp_name']));
$image_name= addslashes($_FILES['poza_caseta']['name']);

move_uploaded_file($_FILES["poza_caseta"]["tmp_name"],"../../../../img/traseu_thmb/" . $_FILES["poza_caseta"]["name"]);

$poza_caseta="img/traseu_thmb/" . $_FILES["poza_caseta"]["name"];

if (!isset($_FILES['poza_header']['tmp_name'])) {
echo "";
}else{
$files=$_FILES['poza_header']['tmp_name'];
$images= addslashes(file_get_contents($_FILES['poza_header']['tmp_name']));
$images_name= addslashes($_FILES['poza_header']['name']);

move_uploaded_file($_FILES["poza_header"]["tmp_name"],"../../../../img/poze_header/" . $_FILES["poza_header"]["name"]);

$poza_header="img/poze_header/" . $_FILES["poza_header"]["name"];

########### Poze Upload #########
error_reporting(0);
define ("MAX_SIZE","9000");
function getExtension($str)
{
$i = strrpos($str,".");
if (!$i) { return ""; }
$l = strlen($str) - $i;
$ext = substr($str,$i+1,$l);
return $ext;
}
$valid_formats = array("jpg", "png", "bmp","jpeg");
if(isset($_POST) and $_SERVER['REQUEST_METHOD'] == "POST")
{

$uploaddir = "../../../../img/gallery/"; //image upload directory
foreach ($_FILES['photos']['name'] as $name => $value)
{

$filename = stripslashes($_FILES['photos']['name'][$name]);
$size=filesize($_FILES['photos']['tmp_name'][$name]);
//get the extension of the file in a lower case format
$ext = getExtension($filename);
$ext = strtolower($ext);

if(in_array($ext,$valid_formats))
{
if ($size < (MAX_SIZE*1024))
{
$image_name=time().$filename;

$newname=$uploaddir.$image_name;

if (move_uploaded_file($_FILES['photos']['tmp_name'][$name], $newname))
{

$sqlz = "INSERT INTO tours (titlu,durata,descriere,pret,ribbon,poza,titlu_slider,desc_slider,poza_slider,descriere_box,titlu_box1,desc_box1,titlu_box2,desc_box2,titlu_box3,desc_box3,titlu_box4,desc_box4,poze_articol) VALUES ('".$_POST["oras_caseta"]."','".$_POST["durata_caseta"]."','".$_POST["descriere_caseta"]."','".$_POST["pret_caseta"]."','".$_POST["icon_caseta"]."','$poza_caseta','".$_POST["titlu_slider"]."','".$_POST["descriere_slider"]."','$poza_header','".$_POST["descriere_overview"]."','".$_POST["titlu_box1"]."','".$_POST["desc_box1"]."','".$_POST["titlu_box2"]."','".$_POST["desc_box2"]."','".$_POST["titlu_box3"]."','".$_POST["desc_box3"]."','".$_POST["titlu_box4"]."','".$_POST["desc_box4"]."')";

$sqlz .= "INSERT INTO poze_articol (poza_slider,pid) VALUES ('img/gallery/$image_name','1')";
$retval = mysql_query( $sqlz, $conn );

echo '<div class="alert alert-success" role="alert">
<strong>Bravo!</strong> Ai adaugat cu succes un traseu pe site.
</div>';
}
}
}
}
}
}
}
}
?>

最佳答案

您无法像连接 $sqlz 变量那样连接 SQL 指令。

您必须一次执行一个 SQL 插入查询。

因此,在第一次 INSERT intotours 之后,您需要执行 mysql_query( $sqlz, $conn )。完成此操作后,您需要通过 INSERT INTO poze_articol 再次重用 $sqlz,然后再次执行 mysql_query( $sqlz, $conn ) 。请尝试以下操作:

$sqlz =  "INSERT INTO tours (titlu,durata,descriere,pret,ribbon,poza,titlu_slider,desc_slider,poza_slider,descriere_box,titlu_box1,desc_box1,titlu_box2,desc_box2,titlu_box3,desc_box3,titlu_box4,desc_box4,poze_articol) VALUES ('".$_POST["oras_caseta"]."','".$_POST["durata_caseta"]."','".$_POST["descriere_caseta"]."','".$_POST["pret_caseta"]."','".$_POST["icon_caseta"]."','$poza_caseta','".$_POST["titlu_slider"]."','".$_POST["descriere_slider"]."','$poza_header','".$_POST["descriere_overview"]."','".$_POST["titlu_box1"]."','".$_POST["desc_box1"]."','".$_POST["titlu_box2"]."','".$_POST["desc_box2"]."','".$_POST["titlu_box3"]."','".$_POST["desc_box3"]."','".$_POST["titlu_box4"]."','".$_POST["desc_box4"]."')";

mysql_query( $sqlz, $conn );

$sqlz = "INSERT INTO poze_articol (poza_slider,pid) VALUES ('img/gallery/$image_name','1')";

mysql_query( $sqlz, $conn );

关于php - INSERT INTO 2表查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47704844/

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