javascript - 尝试创建具有 future 日期的 Javascript 时钟

Question

我正在尝试创建一个从当前日期到 future 3 个月 15 天和 280 年的 Javascript 时钟......到目前为止，我已经设法弄清楚如何让月份和年份稍微显示一下正确...但例如，当前日期显示为“2295 年 12 月 45 日，星期五”，我想弄清楚如何获取它，以便正确的日期显示为 2296 年 1 月 14 日。

到目前为止，这是我的代码:

    function date_time(id)
    {
    date = new Date;
    year = date.getFullYear() + 280;
    month = date.getMonth() + 3;
    months = new Array('January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December');
    if(month = "00") {d = 31} if(d>31);
    if(month = "01") {d = 28} if(d>28);
    if(month = "02") {d = 31} if(d>31);
    if(month = "03") {d = 30} if(d>30);
    if(month = "04") {d = 31} if(d>31);
    if(month = "05") {d = 30} if(d>30);
    if(month = "06") {d = 31} if(d>31);
    if(month = "07") {d = 31} if(d>31);
    if(month = "08") {d = 30} if(d>30);
    if(month = "09") {d = 31} if(d>31);
    if(month = "10") {d = 30} if(d>30);
    if(month = "11") {d = 31} if(d>31);
    d = date.getDate() + 15;
    day = date.getDay();
    days = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');
    if (d < 10) {
        d = "0" + d;
    }
    h = date.getHours();
    if(h<10)
    {
            h = "0"+h;
    }
    m = date.getMinutes();
    if(m<10)
    {
            m = "0"+m;
    }
    s = date.getSeconds();
    if(s<10)
    {
            s = "0"+s;
    }
    result = ''+days[day]+', '+months[month]+' '+d+', '+year+' '+h+':'+m+':'+s;
    document.getElementById(id).innerHTML = result;
    setTimeout('date_time("'+id+'");','1000');
    return true;
    }

Answer 1

没那么难，试试这个。

check fiddle

//3个月15天280

$(document).ready(function(){
 var date = new Date();
 var newDate = new Date(date.getFullYear()+280,date.getMonth()+2,date.getDate()+15);// I m adding 2 to month because it returns from 0-11 not from1-12 thats why for 3 months later i m adding 2.
    alert("Today : "+ date);
    alert("after 3 months and 15 days and 280 Years : "+newDate);
});