javascript - 需要对象比较帮助

Question

我想比较名字，如果匹配，则说我们的名字相似，否则我们的名字不同。但是这段代码在比较名称时给出了输出 undefined。

有人可以帮我理解/解决这个问题吗？

我想获得关注，例如:

We have different names, Bob and I.

function addPersonMethods(obj){
    this.obj = obj;
}

addPersonMethods.prototype.greet = function(str){
    return str + ", my name is "+ this.obj.name;
}

addPersonMethods.prototype.nameshake = function(othername){
    this.othername = othername;
    if (this.obj.name == this.othername){
         console.log("We have the same name ," + this.obj.name + " and I! ");
    }
    else
         console.log("We have different names ," + this.obj.name + " and I.");
}

var bob_def =  { name: 'Bob', age: 21 };
var eve_def =  { name: 'Eve', age: 21 };

var bob = new addPersonMethods(bob_def);
var eve = new addPersonMethods(eve_def);
var another_bob = new addPersonMethods({name:'Bob', age: 40});

console.log(bob.greet("Hi all"));
console.log(eve.greet("Hello"));
console.log(another_bob.greet("Hey"));

console.log(bob.nameshake(eve));

Answer 1

您的 nameshake() 方法需要一个 string(名称)，但您传递的是一个对象，因此比较永远不会是 true。您想要与该对象的 .obj.name 进行比较。

其次，您正在记录 bob.nameshake() 的结果，而该函数实际上并未返回任何内容。

当您想打印其他人的名字时，您在“我们有...”语句中打印您的自己的名字。

function addPersonMethods(obj) {
  this.obj = obj;
}

addPersonMethods.prototype.greet = function(str) {
  return str + ", my name is " + this.obj.name;
}

addPersonMethods.prototype.nameshake = function(otherperson) {
  var othername = otherperson.obj.name;

  if (this.obj.name == othername) {
    console.log("We have the same name, " + othername + " and I! ");
  } 
  else
    console.log("We have different names, " + othername + " and I.");
}


var bob_def = {
  name: 'Bob',
  age: 21
};
var eve_def = {
  name: 'Eve',
  age: 21
};


var bob = new addPersonMethods(bob_def);
var eve = new addPersonMethods(eve_def);
var another_bob = new addPersonMethods({
  name: 'Bob',
  age: 40
});

console.log(bob.greet("Hi all"));
console.log(eve.greet("Hello"));
console.log(another_bob.greet("Hey"));

bob.nameshake(eve);
bob.nameshake(another_bob);