mysql - 根据每位员工的功绩点从最高到最低对每个员工进行排名

Question

创建两个表emp_merits(meritid，empid，date，meritpoints)，emp1(empid，empname)每个员工每月都会根据他们的表现获得功绩点。因此，同一员工可以在表中拥有多个具有不同优点的条目。列出特定员工在特定日期之间获得的所有优点(此处将输入 empid)根据每位员工的功绩点从最高到最低进行排名

到目前为止我已经尝试过这个查询

select   empid , sum (meritpoints) as totalmerits , (DENSE_RANK()OVER (PARTITION BY empid ORDER BY meritpoints desc)) AS rank from emp_merit 
  group by empid,meritpoints 
  order by empid ,totalmerits desc

Answer 1

你可以试试这个:

SELECT @rownum := @rownum + 1 AS rank, a.*  
FROM (
SELECT empid, sum(meritpoints) AS totalmerits
FROM emp_merits 
GROUP BY empid
ORDER BY totalmerits) a, (SELECT @rownum := 0) r ;

您可能需要在 WHERE 子句中指定具体日期。