javascript - 根据键的存在和值对对象数组进行排序

Question

我有一个对象数组。例如-

[{
    aKey:2, 
    bKey:2, 
    cKey:3
}, { 
    bKey:2, 
    cKey:6
}, {
    aKey:1,
    bKey:6, 
    cKey:5
}, {
    bKey:1, 
    cKey:4
}, {
    bKey:6, 
    cKey:7
}]

所以我需要做的是-

1. 首先根据 aKey(asc 顺序)对数组进行排序，具有此键的对象将位于结果数组的开头。
   
2. 然后我需要根据 bKey 的值对数组进行排序。例如，所有 bKey = 2 的记录都位于开头。
   
3. 其余记录将根据 cKey 的值按 asc 顺序排序。
   

所以输出将是-

[{
    aKey:1,
    bKey:6, 
    cKey:5
}, {
    aKey:2, 
    bKey:2, 
    cKey:3
}, { 
    bKey:2, 
    cKey:6
}, {
    bKey:1, 
    cKey:4
}, {
    bKey:6, 
    cKey:7
}]

Answer 1

优先排序从aKey到bKey然后到cKey，你可以使用这个:

var array=[{aKey:2,bKey:2,cKey:3},{bKey:2,cKey:6},{aKey:1,bKey:6,cKey:5},{bKey:1,cKey:4},{bKey:6,cKey:7}]

var result = array.sort(function(hash) {
  return function(a, b) {
    return ((a.aKey || Infinity) - (b.aKey || Infinity)) 
    || ((a.bKey || Infinity) - (b.bKey || Infinity)) 
    || ((a.cKey || Infinity) - (b.cKey || Infinity))
  }
}(Object.create(null)));

console.log(result);

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But you want bKey:2 to come before bKey:1 as for the last element that has aKey, the value of bKey is 2.

要针对此异常进行调整，在完成 aKey 后不知道要跟随哪个元素(并扩展到 bKey 的情况也完成了)，你可以这样做 - 散列这些异常键并相应地排序 - 请参见下面的演示:

var array=[{aKey:2,bKey:2,cKey:3},{aKey:1,bKey:6,cKey:5},{bKey:1,cKey:4},{bKey:6,cKey:7},{bKey:2,cKey:7},{bKey:2,cKey:6},{cKey:4},{cKey:7}]

var result = array.sort(function(hash) {
  return function(a, b) {
    // find the anomaly keys
    a.aKey && !b.aKey && (hash.bkey = a.bKey);
    a.bKey && !b.bKey && (hash.ckey = a.cKey);
    // sort criteria
    return ((a.aKey || Infinity) - (b.aKey || Infinity)) 
    || (((a.bKey != hash.bkey) - (b.bKey != hash.bkey)) || ((a.bKey || Infinity) - (b.bKey || Infinity))) 
    || (((a.cKey != hash.ckey) - (b.cKey != hash.ckey)) || ((a.cKey || Infinity) - (b.cKey || Infinity)))
  }
}(Object.create(null)));

console.log(result);

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