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android - 我试图从 android 将数据插入 mysql 数据库

转载 作者:行者123 更新时间:2023-11-29 17:53:22 25 4
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拜托,我希望有人告诉我我的代码出了什么问题,当我执行它时,数据库中没有任何反应。我不知道我的请求有问题还是其他什么问题。

  1. 我有一个名为 expedition 的表,其中包含以下列:ide、bordereau、agenceorig、nomexped、numexped、nomdestin、numdestin、destination emballage 和 valeur。

  2. 我有一个表格,其中包含:$bordereau、$username、$nomexped、$numexped、$nomdestin、$numdestin、$destination、$emballage、$valeur

  3. 当我使用按钮验证表单时,我会使用私有(private)函数 isexpedition($bordereau) 检查 $bordereau 是否已存在,如果不存在,我会将数据插入表中。

当我执行代码时,我收到以下消息:{"error":true,"message":"Une erreur est survenue, veillez recommencer"},显示数据尚未插入数据库。

/*CRUD -> C -> CREATE*/
public function expedition($nomexped,$numexped,$nomdestin,$numdestin,$destination,$emballage,$bordereau,$valeur){
if($this-> isexpedition($bordereau)){
return 0;
}else{

$stmt = $this->con->prepare("INSERT INTO expedition (ide,bordereau,agenceorig,nomexped,numexped,nomdestin,numdestin,destination,emballage,valeur) VALUES (NULL,?,?,?,?,?,?,?,?,?)");
$stmt->bind_param("sssssssss",$Bordereau,$username,$Nomexped,$Numexped,$Nomdestin,$Numdestin,$Destination,$Emballage,$Valeur);

if($stmt->execute()){
return 1;
}else{
return 2;
}
}
}

private function isexpedition($bordereau){
$stmt = $this->con->prepare("SELECT ide FROM expedition WHERE bordereau=? ");
$stmt->bind_param("s",$bordereau);
$stmt->execute();
$stmt->store_result();
return $stmt->num_rows>0;
}
}

最佳答案

$stmt = $conn->prepare("INSERT INTO users (username,password, email, gender) VALUES (?, ?, ?, ?)");
$stmt->bind_param("ssss", $username, $password, $email, $gender);

//if the user is successfully added to the database
if($stmt->execute()){

//fetching the user back
$stmt = $conn->prepare("SELECT id, id, username, email, gender FROM users WHERE username = ?");
$stmt->bind_param("s",$username);
$stmt->execute();
$stmt->bind_result($userid, $id, $username, $email, $gender);
$stmt->fetch();

$user = array(
'id'=>$id,
'username'=>$username,
'email'=>$email,
'gender'=>$gender
);

$stmt->close();

//adding the user data in response
$response['error'] = false;
$response['message'] = 'User registered successfully';
$response['user'] = $user;
}

关于android - 我试图从 android 将数据插入 mysql 数据库,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49102548/

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