javascript - javascript/jquery 中的对象问题

Question

var node = {
node: {
  name: "someone1",
  city: "somewhere1",
  state: "someplace1"
},
node : {
  name: "someone2",
  city: "somewhere2",
  state: "someplace2"
},
node : {
  name: "someone3",
  city: "somewhere3",
  state: "someplace3"
}
};


console.log(JSON.stringify(node.node));
//Output is {"name":"someone3","city":"somewhere3","state":"someplace3"}

但我需要完整的数据，比如当我输入 node.name 时......所有名称都应该显示

Answer 1

你不应该让对象具有同名的属性，对象中的键应该保持唯一。你可以有一个数组并循环遍历它

var node = [
     {
      name: "someone1",
      city: "somewhere1",
      state: "someplace1"
    },{
      name: "someone2",
      city: "somewhere2",
      state: "someplace2"
    }, {
      name: "someone3",
      city: "somewhere3",
      state: "someplace3"
    }
    ]
    
node.forEach(function(item){
   console.log(item.name);
})

更新:考虑到您在评论中指出的嵌套对象，将值设置为输入。

您需要递归才能找到嵌套对象中的所有名称

$(function(){
var node = {
  "id": "429428",
  "name": "something",
  "state": {
    "filter": "98887"
  },
  "node": {
    "id": "49888",
    "name": "something2",
    "state": {
      "filter": "48765"
    },
    "node": {
      "id": "428866",
      "name": "something3",
      "state": {
         "filter": "998898"
      }
    }
  }
}
var arr = [];
function getValues(node, arr) {
    for (prop in node) {
        console.log(prop);
        if(prop == "name") {
            arr.push(node[prop]);
            
        }
        if(prop == "node") {
            getValues(node[prop], arr)
        }
    }
}

getValues(node, arr)




console.log(arr.join(" "));

document.getElementById('ip').value = arr.join(" ");
})

<input type="text" id="ip"/>