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php - 使用php将csv文件数据插入mysql数据库

转载 作者:行者123 更新时间:2023-11-29 17:48:42 24 4
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This is my html page for adding data

用于将数据插入数据库位置并将 csv 文件插入“eligilist”数据库的 php 脚本。注意:rownd1,rownd2 ....是基于选择轮数的javascript事件,然后javascript代码显示选择框的数量,即rownd1,rownd2,rownd3,因此这些是基于用户选择的值。

<?php
require_once('dbconfig/config.php');
if(isset($_POST['submit']))
{
$name = $_POST['placename'];
$eligibility = $_POST['elig'];
$backlogs=$_POST['blogs'];
$rounds=$_POST['rownds'];

if( isset($_POST["rownd1"]) && isset($_POST["rownd2"] ) && isset($_POST["rownd3"] ) && isset($_POST["rownd4"] ))
{
$round1=$_POST['rownd1'];
$round2=$_POST['rownd2'];
$round3=$_POST['rownd3'];
$round4=$_POST['rownd4'];
}
elseif (isset($_POST["rownd1"]) && isset($_POST["rownd2"] ) && isset($_POST["rownd3"] )) {
$round1=$_POST['rownd1'];
$round2=$_POST['rownd2'];
$round3=$_POST['rownd3'];
$round4=NULL;
}
elseif (isset($_POST["rownd1"]) && isset($_POST["rownd2"] )) {
$round1=$_POST['rownd1'];
$round2=$_POST['rownd2'];
$round3=NULL;
$round4=NULL;
}
elseif (isset($_POST["rownd1"]))
{
$round1=$_POST['rownd1'];
$round2=NULL;
$round3=NULL;
$round4=NULL;
}

$venu=$_POST['location'];
$date=$_POST['InterviewTime'];

$fileName = $_FILES['myFile']['name'];
$fileTmpName = $_FILES['myFile']['tmp_name'];
$fileExtension = pathinfo($fileName,PATHINFO_EXTENSION);
$allowedType = array('csv');
if(!in_array($fileExtension, $allowedType))
{
echo '<script type="text/javascript"> alert("invalid file extension")</script>';
} else{

$handle = fopen($fileTmpName,'r');
while (($myData = fgetcsv($handle,1000,',')) !== FALSE){
$fname = $myData[0];
$regno = $myData[1];
$branch = $myData[2];
$percentage = $myData[3];
$back_logs = $myData[4];
$mobile = $myData[5];
$email = $myData[6];

$query = "INSERT INTO eliglist (sr, fname, regno, branch, percentage, back_logs, mobile, email) VALUES (NULL,".$fname.",".$regno.",".$branch.",".$percentage.",".$back_logs.",".$mobile.",".$email.")";
$query_run = mysqli_query($con,$query);
}

$query1 = "INSERT INTO `placements` (`id`,`name`,`eligibility`,`backlogs`,`rounds`,`round1`,`round2`,`round3`,`round4`,`venu`,`date`) VALUES (NULL,'$name','$eligibility','$backlogs','$rounds','$round1','$round2','$round3','$round4','$venu','$date')";
$query_run1 = mysqli_query($con,$query1);



if($query_run && $query_run1)
{
echo '<script type="text/javascript"> alert("Successfully added")</script>';
}
else
{
echo '<script type="text/javascript"> alert("Error!")</script>';
}

}
}
}
?>

我的问题是,当我提交所有数据以及 csv 文件时,它显示错误...但是除了 csv 文件之外,其余数据都插入到展示位置数据库中,唯一的问题是 csv 文件未存储在数据库中的 Eligilist 表中...如果有任何错误,请帮助我并解决我的代码...谢谢。

最佳答案

您需要在插入内容中的字段值周围加上引号(与展示位置表的操作方式相同)...

$query = "INSERT INTO eliglist (sr, fname, regno, branch, percentage, back_logs, mobile, email) 
VALUES (NULL,'$fname','$regno','$branch','$percentage','$back_logs','$mobile','$email')";

但是您应该使用准备好的语句和绑定(bind)变量,因为这有助于防止出现一些问题...

        $query = "INSERT INTO eliglist (sr, fname, regno, branch, percentage, back_logs, mobile, email)       
VALUES (NULL,?,?,?,?,?,?,?)";

$prep = mysqli_prepare ( $con,$query );
$handle = fopen($fileTmpName,'r');
while (($myData = fgetcsv($handle,1000,',')) !== FALSE){
$fname = $myData[0];
$regno = $myData[1];
$branch = $myData[2];
$percentage = $myData[3];
$back_logs = $myData[4];
$mobile = $myData[5];
$email = $myData[6];

mysqli_stmt_bind_param($prep, "sssssss", $fname,
$regno, $branch, $percentage, $back_logs,
$mobile, $email );
mysqli_stmt_execute($prep);
}

关于php - 使用php将csv文件数据插入mysql数据库,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49584679/

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