android - Web API 服务器 Controller 未获取参数

Question

我从 Android 应用程序发送 JSON 数据。在服务器端，我遇到了问题 - Web API 服务器 Controller 没有获取参数。从客户端我发送这样的 json 数据:

{   "TypeID ": "1",
    "FullName": "Alex",
    "Title": "AlexTitle",
    "RegionID": "1",
    "CityID ": "1",
    "Phone1": "+7(705)105-78-70"
}

感谢任何帮助，如果您有一些信息，想法请告诉我，谢谢!这是 Controller

 [System.Web.Http.HttpPost]
    public HttpResponseMessage PostRequisition([FromBody]string requisition)
    {
        Requisition postReq = new Requisition();
       if (!String.IsNullOrEmpty(requisition))
        {
            dynamic arr = JValue.Parse(requisition);
            //PostReq model = JsonConvert.DeserializeObject<PostReq>(requisition);
            postReq.FullName = arr.FullName;
            postReq.CityID = Convert.ToInt32(arr.CityID);
            postReq.RegionID = Convert.ToInt32(arr.RegionID);
            postReq.TypeID = Convert.ToInt32(arr.TypeID);
            postReq.UserID = 8;
            postReq.Title = arr.Title;
            postReq.Date = Convert.ToDateTime(arr.Date, CultureInfo.CurrentCulture);
            postReq.Decription = arr.Description;
            postReq.Phone1 = arr.Phone1;
            postReq.Activate = false;
            postReq.ClickCount = 0;
            try
            {
                db.Requisition.Add(postReq);
                db.SaveChanges();
                Message msg = new Message();
                msg.Date = DateTime.Now;
                msg.Type = "POST";
                msg.Text = "OK";
                db.Message.Add(msg);
                db.SaveChanges();
                return Request.CreateResponse(HttpStatusCode.OK, postReq);
            }
            catch (Exception ex)
            {
                Message msg = new Message();
                msg.Date = DateTime.Now;
                msg.Type = "POST";
                msg.Text = "ERROR";
                db.Message.Add(msg);
                db.SaveChanges();
                return Request.CreateResponse(HttpStatusCode.OK, ex.Message);
            }
        }
        else
        {
            Message msg = new Message();
            msg.Date = DateTime.Now;
            msg.Type = "POST";
            msg.Text = "null";
            db.Message.Add(msg);
            db.SaveChanges();
            return Request.CreateResponse(HttpStatusCode.OK, "null");
        }

    }

Answer 1

你的问题很简单。您正在发送一个 JSON 对象，但期望在您的 POST 操作中有一个字符串。解决此问题的简单方法是创建一个映射到您的 JSON 对象的类:

public class RequisitionViewModel
{
    public int TypeID {get; set;}
    public string FullName {get; set;}
    public string Title {get; set;}
    public int RegionID {get; set;}
    public int CityID  {get; set;}
    public string Phone1 {get; set;}    
}

然后，将您的 Action 签名更改为:

[FromBody]RequisitionViewModel requisition)

您也不需要代码中的所有转换:

postReq.FullName = requisition.FullName;
postReq.CityID = requisition.CityID;
//other fields...